If 22% are sixth graders, then the rest must not sixths graders.
100% of the school - 22% sixth grades = 78% are not sixths graders
Answer:
This is easy -- it's just a list of steps. At this level, the problems are pretty simple.
Let's just do one, then I'll write out the list of steps for you.
Find the inverse of f( x ) = -( 1 / 3 )x + 1
STEP 1: Stick a "y" in for the "f(x)" guy:
y = -( 1 / 3 )x + 1
STEP 2: Switch the x and y
( because every (x, y) has a (y, x) partner! ):
x = -( 1 / 3 )y + 1
STEP 3: Solve for y:
x = -( 1 / 3 )y + 1 ... multiply by 3 to ditch the fraction ... 3x = -y + 3 ... ditch the +3 ... subtract 3 from both sides ... 3x - 3 = -y ... multiply by -1 ... -3x + 3 = y ... y = -3x + 3
STEP 4: Stick in the inverse notation, f^( -1 )( x )
f^( -1 )( x ) = -3x + 3
Step-by-step explanation:
Answer:
77 nickels
106 dimes
Step-by-step explanation:
Let there be n nickes and d dimes
Since there are 183 coins, we can write:
n + d = 183
Also, the value of nickel is 0.05 and dime is 0.1, total value is 14.45, so we can write:
0.05n + 0.1d = 14.45
Solving 1st equation for n, we have:
n = 183 - d
Putting this into 2nd equation and solving for d:

There are 106 dimes
Since, n = 183 - d
n = 183 - 106
n = 77
There are 77 nickels
Answer:
C
Step-by-step explanation:
In the attached file