Simplify !! answer choices: 4^5/6 4^3/2 4^1/6 4^1/3

Mathematics

1 answer:

Alenkinab [10]3 years ago

5 0

Answer:

Step-by-step explanation:

In the attached file

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the radius of the aluminum atom is 143pm. the radius of the aluminum atom is 54pm. by what percentage did the radius change as t

Dennis_Churaev [7]

Answer:

There was 62.23% change in radius as the ion formed.

Step-by-step explanation:

Given

Radius of Aluminium $(Al)$ atom = 143 pm

Radius of Aluminium $(Al^{3+})$ atom = 54 pm

Change is the radius = Radius of Aluminium $(Al)$ atom - Radius of Aluminium $(Al^{3+})$ atom = 143 -54 = 89

Now to find % Change is the radius we will divide Change is the radius by Radius of Aluminium $(Al)$ atom and multiply by 100 we get

% Change is the radius = $\frac{\textrm{Change is the radius}}{\textrm{Radius of Aluminium (Al) atom}} \times 100 = \frac{89}{143}\times100= 62.23\%$

Hence there was 62.23% change in radius as the ion formed.

4 0

4 years ago

The endpoints of the diameter of a circle have the coordinates (3, 8) and (9, 16).

Alexxx [7]

The coordinates of the center of this circle will be the average between the extreme points

C = ( (xo+x1)/2 , (yo+y1)/2)

Where,

xo = 3 and x1 = 9

yo = 8 and y1 = 16

Then us stay with"

C = ( (3+9)/2 , (8+16)/2)

C = ( 12/2 , 24/2)

C = ( 6 , 12 )

3 0

3 years ago

Help me with this one please

Nataliya [291]

Answer:

Step-by-step explanation:

${a}^{0} = 1 \\ \frac{ {a}^{n} }{ {a}^{m} } = {a}^{n - m} \\ {a}^{n} \times {a}^{m} = {a}^{n + m}$