All categories

3 years ago

Read the sentence.

Mathematics

1 answer:

valina [46]3 years ago

5 0

Answer:

The last one

Step-by-step explanation:

For is a prepostion. One way to identify prepostions is to use the squirriel trick. Think of a word and then use this sentence starter. The squirrel is ___ the tree. In this case, for fits with it. Another prepostion is in or of. I hope this helps.

You might be interested in

What are the roots of the equation 4x2 = 36x – 87 in simplest a + bi form?

sammy [17]

Answer:

x = 87/28

Step-by-step explanation:

6 0

3 years ago

A contracting company rents a generator for 6 hours and a heavy duty saw for 6 hours total cost of $48 for another job the compa

Wewaii [24]

Answer:

the hourly rates are $8 and $10 respectively

Step-by-step explanation:

Given that

The generator rents for 6 hours and the total cost is $48

And, for another job The generator rents for 4 hours and the total cost is $40

We need to find out the hourly rates

For the first one

= $48 ÷ 6 hours

= $8

For the second one

= $40 ÷ 4 hours

= $10

Hence, the hourly rates are $8 and $10 respectively

6 0

3 years ago

Which statements are true about the trigonometric ratios of this triangle

rosijanka [135]

Answer:

Options (1), (2), (3) and (4)

Step-by-step explanation:

By applying the sine and cosine rules in the given triangle,

sinθ = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

cosθ = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

cos(30°) = $\frac{AC}{AB}$

= $\frac{11\sqrt{3} }{22}$

= $\frac{\sqrt{3}}{2}$

sin(30°) = $\frac{BC}{AB}$

= $\frac{11}{22}$

= $\frac{1}{2}$

cos(60°) = $\frac{BC}{AB}$

= $\frac{11}{22}$

= $\frac{1}{2}$

sin(60°) = = $\frac{AC}{AB}$

= $\frac{11\sqrt{3} }{22}$

= $\frac{\sqrt{3}}{2}$

Options (1), (2), (3) and (4) are the correct options.

3 0

3 years ago

If z^2+1/z^2=11 , find the value of z^3-1/z^3,using only the positive value of z-1/z

vredina [299]

Hello,

Let's assume

$t=z- \dfrac{1}{z} \\\\

t^2=z^2-2+ \dfrac{1}{z^2}= 11-2=9==\ \textgreater \ t=3\\\\

t^3=z^3-3z^2* \dfrac{1}{z} +3z* \dfrac{1}{z^2} - \dfrac{1}{z^3} \\\\
=z^3 - \dfrac{1}{z^3} -3(z-\dfrac{1}{z})\\\\
z^3 - \dfrac{1}{z^3}=t^3+3t=3^3+9=27+9=36


$