<h2><u>
Answer:</u></h2>
Which ordered pairs are in the solution set of the system of linear inequalities?
y > Negative one-halfx
y < One-halfx + 1
On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0, 0) and (4, negative 2). Everything above the line is shaded. The second dashed line has a positive slope and goes through (negative 2, 0) and (2, 2). Everything below the line is shaded.
(5, –2), (3, 1), (–4, 2)
(5, –2), (3, –1), (4, –3)
<h2><u>
(5, –2), (3, 1), (4, 2)</u></h2>
(5, –2), (–3, 1), (4, 2)
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
2a+ 2/a =4
Multiply each side by a to clear the fraction
a( 2a+ 2/a) =4*a
Distribute
2a^2 +2 = 4a
Subtract 4a from each side
2a^2 -4a +2 = 4a-4a
2a^2 -4a +2 =0
Divide by 2
2/2 a^2 -4a/2 +2/2 =0/2
a^2 -2a +1=0
Factor
(a-1) (a-1) =0
Using the zero product property
a=1
2a^2 -2/a^2
2(1)^2 -2/1^2
2-2
0
Answer:
102.5, 103.5
Step-by-step explanation:
a+a+1=206
2a+1=206
2a=205
a=102.5
103.5
I think there is a bug here. They can't be whole numbers.
8y^2 + 12x - 4y^2 + 24x
= 4y^2 + 36x
.25 or 1/4 Is the simplest form
