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scoray [572]
3 years ago
8

it costs 13$ for admission to amusement park, plus 1.50$ for each ride.if you have a total of 35.50 to spend, what is the greate

st number of rides you can go on
Mathematics
1 answer:
ICE Princess25 [194]3 years ago
3 0

Answer:

<em>Thus, the greatest number of rides I can go on is 15 rides</em>

Step-by-step explanation:

I have $35.50 to spend for admission plus rides in the amusement park.

Admission costs $13. That leaves me with

$35.50 - $13 = $22.50

to spend on rides.

Considering each ride costs $1.50, we can find the maximum number of rides by dividing the remaining money by the cost per ride as follows:

$22.50 / $1.50 = 15

Thus, the greatest number of rides I can go on is 15 rides

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3 years ago
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A function f is described by f(x)=A*exp(kx)+B, where A, B and k are constants. Given f(0)=1, f(1)=2, and that the horizontal asy
s2008m [1.1K]

Answer:

k = ln (6/5)

Step-by-step explanation:

for

f(x)=A*exp(kx)+B

since f(0)=1, f(1)=2

f(0)= A*exp(k*0)+B = A+B = 1

f(1) = A*exp(k*1)+B =  A*e^k + B = 2

assuming k>0 , the horizontal asymptote H of f(x) is

H= limit f(x) , when x→ (-∞)

when x→ (-∞) , limit f(x) =  limit (A*exp(kx)+B) = A* limit [exp(kx)]+B* limit = A*0 + B = B

since

H= B = (-4)

then

A+B = 1 → A=1-B = 1 -(-4) = 5

then

A*e^k + B = 2

5*e^k + (-4) = 2

k = ln (6/5)    ,

then our assumption is right and k = ln (6/5)  

8 0
3 years ago
. Write an equation for the line parallel to y = 7x + 11 that contains P(-5, 7).
m_a_m_a [10]
A) x – 7 = -7(6y + 5)

x – 7 = -42y + -35

x – 7 + 35 = -42y

x + 28 = -42y

y = (1/42)x – 14/21

c) y – 7 = 7(x + 5)

y – 7 = 7x + 35

y = 7x + 42

b) y – 7 = -7(x + 5)

y – 7 = -7x -35

y = -7x – 28

d) y + 7 = 7(x + 5)

y + 7 = 7x + 35

y = 7x + 28
3 0
3 years ago
2(f^4)^2f^2<br> ——————-<br> 8f^12
azamat

Answer:

=2f^10

Step-by-step explanation:

6 0
3 years ago
Consider the following function.
goldfiish [28.3K]
We have that
<span>f(x) = (3/2)*x + 4

case 1) for x=-8
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point (-8,-8)

case 2) for x=-4
f(-4) = (3/2)*(-4) + 4--------> -2
point (-4,-2)

case 3) for x=-2
f(-2) = (3/2)*(-2) + 4--------> 1
point (-2,1)

case 4) for x=0
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point (0,4)

case 5) for x=2
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point (2,7)

case 6) for x=4
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point (4,10)

using a graph tool
see the attached figure

6 0
3 years ago
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