Answer:
The coordinates of H′ are (-2,0).
Step-by-step explanation:
It is given that square EFGH stretches vertically by a factor of 2.5 with respect to the x-axis to create rectangle E′F′G′H′.
If a figure stretches vertically by a factor of 2.5 with respect to the x-axis, then the x-coordinates remains same and the points which lie on the axis are also remains the same after stretch.
It is given that the coordinates of H are (-2,0). This point lie on the x-axis, therefore it will remains the same after stretch.
Therefore the coordinates of H′ are (-2,0).
Using the cosine rule we can work out the length of the side opposite the indicated right angle which came to be 15mm
then the final answer came to be 163mm^2
Answer:
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Step-by-step explanation:
Brainiest ududhdhxhc
Let's see this original ewuation:
1) Substitute 4 in for x:
2)Subtract 4 from both sides. This cancels out four.
3)Cancel:
4)Multiply both sides by negative 1:
I think its all of the above ?? sorry if its wrong
