Answer: 3
Step by step explanation
Answer:
![\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}](https://tex.z-dn.net/?f=%5Cboxed%7Bf%28x%29%20-%20g%28x%29%20%3D%202x%282x%5E%7B2%7D%20%2B%20x%20%2B%201%29%7D)
Step-by-step explanation:
f(x) = 9x³ + 2x² - 5x + 4; g(x)=5x³ -7x + 4
Step 1. Calculate the difference between the functions
(a) Write the two functions, one above the other, in decreasing order of exponents.
ƒ(x) = 9x³ + 2x² - 5x + 4
g(x) = 5x³ - 7x + 4
(b) Create a subtraction problem using the two functions
ƒ(x) = 9x³ + 2x² - 5x + 4
-g(x) = <u>-(5x³ - 7x + 4)
</u>
ƒ(x) -g(x)=
(c). Subtract terms with the same exponent of x
ƒ(x) = 9x³ + 2x² - 5x + 4
-g(x) = <u>-(5x³ - 7x + 4)
</u>
ƒ(x) -g(x) = 4x³ + 2x² + 2x
Step 2. Factor the expression
y = 4x³ + 2x² + 2x
Factor 2x from each term
y = 2x(2x² + x + 1)
![\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}](https://tex.z-dn.net/?f=%5Cboxed%7Bf%28x%29%20-%20g%28x%29%20%3D%202x%282x%5E%7B2%7D%20%2B%20x%20%2B%201%29%7D)
Answer:
C. 1.2x
Step-by-step explanation:
He pays 1 x for his haircut, and an additional 20% on top of that, or an additional 0.2x. If you write that as an expression, you can simplify it like this:
![1x+0.2x\\1.2x](https://tex.z-dn.net/?f=1x%2B0.2x%5C%5C1.2x)
You can also work it out by multiplying by 1.2 as stated in answer C. If his haircut costs $10, adding a 20% tip of $2 is the same as multiplying by 1.2.
![10\times1.2=12](https://tex.z-dn.net/?f=10%5Ctimes1.2%3D12)
The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>
Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100
![200 \times a + 100 \times c = 2100](https://tex.z-dn.net/?f=200%20%5Ctimes%20a%20%2B%20100%20%5Ctimes%20c%20%3D%202100)
200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>
Thus the cost of children’s ticket is $ 5
Answer:
Check whether the first and last terms of the trinomial are perfect squares.
Multiply the roots of the first and third terms together.
Compare to the middle terms with the result in step two
If the first and last terms are perfect squares, and the middle term’s coefficient is twice the product of the square roots of the first and last terms
Step-by-step explanation: