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2 years ago

Justify each statement with a property of equality, a property of congruence, or a

Mathematics

1 answer:

LenKa [72]2 years ago

3 0

Reflexive property of Equality is your answer!

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Mary,Tom,Sophia & Isaac share minutes on their cell phone plan. Mary used 1/4 of the minutes,Tom used 0.5 of the minutes,and

nataly862011 [7]

Hello there! So, 1/4 is equivalent to 0.25, which is 25% in percent form. 0.5 is 50% and 0.2 is 20% in percent form. 50 + 20 + 25 is 95. 100 - 95 is 5. Issac can use 5% of the minutes on the cell phone plan. The answer is D: 5%.

5 0

3 years ago

F(x)=2x+1; g(x)=3x-2 find (f+g) (3)

baherus [9]

Step-by-step explanation:

GIVEN,

f(x)=2x+1; g(x)=3x-2

NOW,

( 2x+1 + 3x-2)×3

=(5x-2)×3

=15x - 6 ANSWER

3 0

3 years ago

A small combination lock on a suitcase has 55 wheels, each labeled with the 10 digits 0 to 9. How many 55 digit combinations ar

den301095 [7]

Suppose $a_n$ is the number of possible combinations for a suitcase with a lock consisting of $n$ wheels. If you added one more wheel onto the lock, there would only be 9 allowed possible digits you can use for the new wheel. This means the number of possible combinations for $n+1$ wheels, or $a_{n+1}$ is given recursively by the formula

$a_{n+1}=9a_n$

starting with $a_1=10$ (because you can start the combination with any one of the ten available digits 0 through 9).

For example, if the combination for a 3-wheel lock is 282, then a 4-wheel lock can be any one of 2820, 2821, 2823, ..., 2829 (nine possibilities depending on the second-to-last digit).

By substitution, you have

$a_{n+1}=9a_n=9^2a_{n-1}=9^3a_{n-2}=\cdots=9^na_1=10\times9^n$

This means a lock with 55 wheels will have

$a_{55}=10\times9^{54}$

possible combinations (a number with 53 digits).

7 0

2 years ago

8k + 2m = 3m + k Solve for k

mina [271]

Minus both sides by 2m
$8k = 3 m - 2m + k \\ 8k = m + k$
Minus both sides by k
$7k = m$
Divided both sides by 7
$k = \frac{m}{7}$

6 0

2 years ago

in the equation 6x – 2 = –4x + 2, Spencer claims that the first step is to add 4x to both sides. Jeremiah claims that the first

trapecia [35]

Spencer would be the correct one because it's easier to keep your variables positive when trying to solve. Therefore, in order to keep the variable positive, one would have to add 4x to both sides.

4 0

3 years ago

Read 2 more answers