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Arte-miy333 [17]
3 years ago
5

What are the steps for evaluating 3x7-4^(2)?

Mathematics
2 answers:
natima [27]3 years ago
7 0

Answer:

5

Step-by-step explanation:

first multiply 3 by 7 as 3x7=21

again find the square of 4 as 4^2=16

finally, subtract 16 from 21 as 21-16= 5

Tpy6a [65]3 years ago
3 0

Answer:

5

Step-by-step explanation:

If the expression is 3 × 7 - 4^{2} :

  1. 4^{2} = 4 × 4 = 16
  2. Plug 16 in: 3 × 7 - 16
  3. 3 × 7 = 21
  4. Plug 21 in: 21 - 16
  5. 21 - 16 = 5
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Step-by-step explanation

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The vertex angle of an isosceles triangle measures 42°. A base angle in the triangle has a measure given by (2x + 3)°. What is t
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An isosceles triangle is one in which 2 angles have similar measure while the other one is different. In this case, the 2 vertex angles have a measure of 42 degrees, therefore the third angle which is equal to (2x + 3) is:

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A grasshopper jumps straight up from the ground with an initial vertical velocity of 8 feet per second. After how many seconds w
vlabodo [156]

Answer:

Problem 1 : After 0.25 s

Problem 2 : The squirrel doesn't reach the ground before the nut

Step-by-step explanation:

Problem 1

This is a standard physics problem

The equation that defines the movement of the grasshopper given the initial velocity, and the acceleration is the following

Distance =  Do + Vo*t + 0.5*a*t^2

Where

Do is the initial distance.

(Do = 0, because the grasshopper is on the ground and we choose the reference system there)

Vo is the initial velocity = 8 feet/sec

a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 = - 32.174 feet per second per second.)

t is the time

We substitute in the equation, and solve for t (time)

Distance =  Do + Vo*t + 0.5*a*t^2

(1 foot)=  (0)+ (8 feet/s)*t + 0.5*(-32.174 feet/s^2)*t^2

Solving this equation, we get that

t = 0.25 s

Problem 2

This problem is similar to the previous one

We apply the same formula

D =  Do + Vo*t + 0.5*a*t^2

But in this case, we are going in the opposite direction, and we have an initial distance.

Do = 27 feet

Vo is the initial velocity of the nut = -6 feet/s

D = 0  (Ground)

We substitute in the equation, and solve for t (time)

(0) =  (27) + (-6 feet/s)*t + 0.5*(-32 feet/s^2)*t^2

t = 1.125 s  <  2s

The nut reaches ground in 1.125 s, so the squirrel doesn't reach the ground before the nut

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