s = hours it takes the small pipe on its own.
L = hours it takes the large pipe on its own.
we know the small pipe can do it in 11 hours total, so s = 11, so, how much of the whole job has the small done in 1 hour only?
well, if it takes 11 hours to do the whole thing, in 1 hour it has done only 1/11 of the whole job.
we know both pipes working together can do it in 6 hours flat. So in 1 hour only, both of them have done only 1/6 of the whole thing.
in that 1 hour, how much has the large one done? well, it has only done 1/L of the job.

and you can round that up as needed.
i don't understand this question but I will say 1/3/4
Answer: x=4
Step-by-step explanation:
Answer:
5/12
Step-by-step explanation:
5/6 divided by 2
= 5/6 divided by 2/1
= 5/6 x 1/2
= 5 x 1 over 6 x 2
= 5 over 6 x 2
= 5 / 12