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shtirl [24]
3 years ago
12

Which phrase describes the algebraic expression 7/8y-3​

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
4 0

The algebraic expression uses the terms to denote symbols

sum of means addition

difference of means subtraction

product of means multiplication

quotient of means division

Here we have the term 6x

which actually means 6 times x or

6 multiplied by x

hence by multiplication we use the word product of

so we have the product of 6 and a number as our right answer

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lidiya [134]

Answer:

y = square root x2 - 5

Step-by-step explanation:

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Algebra!!!<br> 3 Questions Only take if you know ALL Answers<br> PLZZZ QUICK
vitfil [10]

Answer:

1. -7.5

2. $1

3. 40

Step-by-step explanation:

For number 1, it can be solved by using the PEMDAS method, or see explanation below:

6x - 4x - 36 = 6 - 2x

2x - 36= -2x + 6

4x + 36 = 6

4x = -30

x = -15/2 or -7.5

For number 2, substitute 3 into both equations:

f(x) =1.50(3) + 2.00

and

f(x) = 2.00(3) + 1.50

This would get $6.50 and $7.50, which, if subtracted, gets $1.

For number 3, do something similar to the previous problem. Substitute 3 for x. It would be 5(2^3), or 40.

Hope this helps!

7 0
3 years ago
Use the figure below to determine the length of sides b and c. options: b = 5√3, c = 10 b =10, c = 5√3 b = 5√2, c = 10√3 b = 5,
Reil [10]

Answer:

A

Step-by-step explanation:

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Find the measures of the angles of the triangle whose vertices are A = (-3,0) , B = (1,3) , and C = (1,-3).A.) The measure of ∠A
alekssr [168]

Answer:

\theta_{CAB}=128.316

\theta_{ABC}=25.842

\theta_{BCA}=25.842

Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

We're going to use the distance formula to find the length of the sides:

r= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}

AB= \sqrt{(-3-1)^2+(0-3)^2}=5

BC= \sqrt{(1-1)^2+(3-(-3))^2}=9

CA= \sqrt{(1-(-3))^2+(-3-0)^2}=5

we can use the cosine law to find the angle:

it is to be noted that:

the angle CAB is opposite to the BC.

the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

BC^2 = AB^2+CA^2-(AB)(CA)\cos{\theta_{CAB}}

\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}

\cos{\theta_{CAB}}=\dfrac{9^2-(5^2+5^2)}{-2(5)(5)}

\theta_{CAB}=\arccos{-\dfrac{0.62}}

\theta_{CAB}=128.316

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}

\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)

\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)

\theta_{ABC}=\arcsin{0.4359}\right)

\theta_{ABC}=25.842

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

\theta_{BCA}=25.842

this can also be checked using the fact the sum of all angles inside a triangle is 180

\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180

25.842+128.316+25.842

180

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