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VARVARA [1.3K]
3 years ago
7

1. Triangle ABC is similar to triangle JKL.

Mathematics
1 answer:
Fittoniya [83]3 years ago
8 0
1. It's all about pattern matching, as a lot of math is.
Letter A corresponds to letter J, as both are first in the names of their respective triangles.
Letter B corresponds to letter K, as both are second in the triangle names. Likewise, letter C corresponds to letter L, as both are last.

Realizing this, it should not be too much of a stretch to see
   ∠B ⇒ ∠K
   ∠C ⇒ ∠L
   AC ⇒ JL
   BC ⇒ KL

2. Same deal. Match the patterns. Here, you're counting rings in the angle marks.
   1 ⇒ 1, so A ⇒ R
   2 ⇒ 2, so B ⇒ Q
since the figures are reportedly similar, you can continue in the same order to finish.
   ABCD ~ RQPS

3. The marked triangles cannot be similar. There are a number of ways to figure this. Basically, you want the ratios of sides to be the same for any similar triangles.

Here, you can eliminate the marked ones because the short side is too short relative to the others. (The average of the other two sides is double the short side in the similar triangles.)

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(06.02 mc) the equation of line cd is y=3x-3. Write an equation of a line perpendicular to line cd in slope intercept form that
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Answer:

y = - \frac{1}{3} x + 2

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The equation of a line in slope- intercept form is

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Read 2 more answers
HELLLPP ME PLEASSEEE!!!!!
antoniya [11.8K]

The similar circles P and Q can be made equal by dilation and translation

  • The horizontal distance between the center of circles P and Q is 11.70 units
  • The scale factor of dilation from circle P to Q is 2.5

<h3>The horizontal distance between their centers?</h3>

From the figure, we have the centers to be:

P = (-5,4)

Q = (6,8)

The distance is then calculated using:

d = √(x2 - x1)^2 + (y2 - y1)^2

So, we have:

d = √(6 + 5)^2 + (8 - 4)^2

Evaluate the sum

d = √137

Evaluate the root

d = 11.70

Hence, the horizontal distance between the center of circles P and Q is 11.70 units

<h3>The scale factor of dilation from circle P to Q</h3>

We have their radius to be:

P = 2

Q = 5

Divide the radius of Q by P to determine the scale factor (k)

k = Q/P

k = 5/2

k = 2.5

Hence, the scale factor of dilation from circle P to Q is 2.5

Read more about dilation at:

brainly.com/question/3457976

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False. Supplementary angles have to add up to 180 degrees, and that is clearly not a flat line lol

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