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Ratling [72]
3 years ago
12

Jen bought 5cds for 20.50 what was the unit price?

Mathematics
2 answers:
kondor19780726 [428]3 years ago
3 0
You answer is 4 dollars and 10 cents
victus00 [196]3 years ago
3 0
The unit price is $4.10 because 20.50 divided by 5 is 4.1
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Derek buys a house for £150,000
Elden [556K]

Answer:

cost price=$150,000

selling price =$154,000

profit= $154,000-$150,000=$4,000

Therfore Percentage Profit= 4,000÷15,000×100=2.7%

Percentage Profit =2.7%

7 0
3 years ago
Question 3 Please. I'm really stuck :(
Stells [14]
Let ∠RTS=∠RST = a (say)
 ∠QUA=∠QSU= b(say)
then we know , at point S, a+40+b=180. so, a+b=140 we'll use this later.

consider trianglePQR, ∠P+∠Q+∠R=180
i.e.P+(180-2b)+(180-2a)=180
P+180+180-2(a+b)=180 ⇒P+180-2(a+b)=0 ⇒P=2(140)- 180=280-180=100
hence,answer is E
7 0
3 years ago
Read 2 more answers
What is the value of the expression w – 4 when w = –17?
JulsSmile [24]
=(-17) - 4
=(-17) + (-4)
=(-21)

3 0
3 years ago
Read 2 more answers
1) Triangle ABC is a similar to triangle QRS by the AA Similarity Postulate
kupik [55]
The m<B for question 1 is 46 degrees, for question 2 the m<Y is one hundred and seventeen degrees.
8 0
3 years ago
Topic: The Quadratic Formula
Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

x= \frac{-b +- \sqrt{b^2-4ac} }{2a}

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² =  x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\=  -4 or 1

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0
3 years ago
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