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Triss [41]
3 years ago
9

The transport tissues of vascular plants are the _____ and _____. xylem; cortex phloem; pith xylem; phloem parenchyma; collenchy

ma
Biology
1 answer:
Juliette [100K]3 years ago
6 0
The answer is <span>xylem and phloem.

Xylem and phloem are the transport tissues of vascular plants. </span><span>Parenchyma and collenchyma are ground tissue, while pith and cortex are stem tissue.
</span><span>Xylem and phloem provide transportation of water, minerals, food, and nutrients. Xylem transport water and minerals from the root to the upper parts of the plant. Phloem transports food and nutrients from the leaves, where they are produced, to the growing or storage parts of the plants.


</span>
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A hawk eats a mouse. This kills the mouse, but it also means that the remaining mice will not have to compete as much for food w
iVinArrow [24]

Answer:

The two organisms are in a predator-prey relationship.

Explanation

because the hawk is the predator, it ate the mouse, and th mouse was they prey, it was eaten

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3,5,6,4,1,2

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People who are tune deaf are unable to follow a rhythm. Scientists have evidence that tune deafness can be genetic. The pedigree
butalik [34]

Question

Pedigree attached

a. Provide evidence from the pedigree that conclusively shows that the tune deafness allele is autosomal dominant, not autosomal recessive. Explain your reasoning.

b. Identify the genotypes of individuals 5 and 6, and then draw the Punnett square for the cross of these two individuals.

c. Compare the expected percentage of each phenotype of the offspring from the cross in part (b) with the actual percentage of each phenotype observed in the children of individuals 5 and 6.

Answer/Explanation:

a. Autosomal dominant means that even having one copy of the allele T will produce a tune deaf individual. The evidence of this is that individuals II.3 and 4 have children (III. 8 and 9) with normal tune perception. This suggests that they have inherited the normal allele from both parents. That means II.3 and II4 must be heterozygous, in order to pass on the normal allele. This makes sense if tune deafness is dominant (because 3 and 4 will both be Tt and Tt, so can pass on the t alleles). However, if tune deafness was recessive, that would mean that individual II 3 and 4 both have to carry 2 copies, meaning there is no way their children would have normal tune perception.

b. Since individual 5 is unaffected and we know this is the recessive trait, they must be Tt. Since individual 6 is affected, they must be either Tt or tt. However, they have children who are unaffected (11, 12, 13) who must be tt. This means, individual 6 must have the t allele to pass on, and must be Tt. Therefore, the cross between individuals 5 and 6 is tt x Tt:

         T        t

t        Tt       tt

t       Tt       tt

c) The punnet square shows the children from (b) have a 50:50 chance of being tune deaf vs normal tune perception (50% each). In contrast, the actual ratios are 25% tune deaf to 75% normal tune perception. (1:4). This deviates from the expected ratio, but since all of these are due to chance, it is not an unexpected occurrence. Perhaps if there were 10, 50 or 100 children (!) from this cross, the results would be more like the expected ratio

5 0
3 years ago
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