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JulsSmile [24]
3 years ago
6

Which of the following is the best approximation for the product of 42.081 x 99.91?

Mathematics
1 answer:
Katarina [22]3 years ago
6 0
The one with two decimals! But show them?
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The rectangular model is made up of squares. Each square is of equal size.
IrinaK [193]
H 45%
you would add up the number of shaded squares and divide that by the total number of squares
6 0
2 years ago
Read 2 more answers
Evaluate 12x−3y when x=−14 and y=3
Amiraneli [1.4K]

12x - 3y

12(-14) - 3(3)

-168 + 9

-159

Hope this helps!! :)

4 0
2 years ago
Read 2 more answers
If you get both of these questions right I will give you 50 points
Stella [2.4K]

Answer:

1) c 226

2)

1. E

2. D

3. B

4. A

5. C

Step-by-step explanation:

6^3=216

5x(4-2)

5x2=10

216+10=226

8 0
2 years ago
4. Find the standard from of the equation of a hyperbola whose foci are (-1,2), (5,2) and its vertices are end points of the dia
Ad libitum [116K]

The <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

<h3>How to find the standard equation of a hyperbola</h3>

In this problem we must determine the equation of the hyperbola in its <em>standard</em> form from the coordinates of the foci and a <em>general</em> equation of a circle. Based on the location of the foci, we see that the axis of symmetry of the hyperbola is parallel to the x-axis. Besides, the center of the hyperbola is the midpoint of the line segment with the foci as endpoints:

(h, k) = 0.5 · (- 1, 2) + 0.5 · (5, 2)

(h, k) = (2, 2)

To determine whether it is possible that the vertices are endpoints of the diameter of the circle, we proceed to modify the <em>general</em> equation of the circle into its <em>standard</em> form.

If the vertices of the hyperbola are endpoints of the diameter of the circle, then the center of the circle must be the midpoint of the line segment. By algebra we find that:

x² + y² - 4 · x - 4 · y + 4= 0​

(x² - 4 · x + 4) + (y² - 4 · y + 4) = 4

(x - 2)² + (y - 2)² = 2²

The center of the circle is the midpoint of the line segment. Now we proceed to determine the vertices of the hyperbola:

V₁(x, y) = (0, 2), V₂(x, y) = (4, 2)

And the distance from the center to any of the vertices is 2 (<em>semi-major</em> distance, a) and the semi-minor distance is:

b = √(c² - a²)

b = √(3² - 2²)

b = √5

Therefore, the <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

To learn more on hyperbolae: brainly.com/question/27799190

#SPJ1

5 0
1 year ago
Which operation is NOT closed for polynomials?
MAXImum [283]

Answer:

  • Option D

Step-by-step explanation:

When you add, multiply or subtract polynomials, the operation results in another polynomial.

When dividing polynomials, the operation may not result in another polynomial. In this case you normally end up with rational expression in the fraction form.

This operation is said not closed.

In our case this is option D.

4 0
2 years ago
Read 2 more answers
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