Answer:
See explanation
Step-by-step explanation:
In the figure below, segment CD is parallel to segment EF, DE is a transversal, then angles DIH and HGI are congruent as alternate interior angles when two parallel lines are cut by a transversal.
Consider triangles DIH and EGH. In these triangles,
as alternate interior angles;
as vertical angles;
because point H bisects segment DE (given).
Thus,
by AAS postulate
Answer:
19,680
Step-by-step explanation:
1 lb = 16 ounces
1230 lb = 1230 * 16 ounces = 19,680 ounces
The absolute value inequality can be decomposed into two simpler ones.
x < 0
x > -8
<h3>
</h3><h3>
Which two inequalities can be used?</h3>
Here we start with the inequality:
3|x + 4| - 5 < 7
First we need to isolate the absolute value part:
3|x + 4| < 7 + 5
|x + 4| < (7 + 5)/3
|x + 4| < 12/3
|x + 4| < 4
The absolute value inequality can now be decomposed into two simpler ones:
x + 4 < 4
x + 4 > - 4
Solving both of these we get:
x < 4 - 4
x > -4 - 4
x < 0
x > -8
These are the two inequalities.
Learn more about inequalities:
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<span>
<span>first off your answer is 21.90 and the step by step i wrote it for you:) Finding the
square root of a number is the inverse
operation of squaring that number. Remember, the square of a number
is that number times itself. </span>
The perfect
squares are the squares of the whole numbers.
The square root
of a number, n, written below is the number that gives n when multiplied by
itself.
</span> <span>Many mathematical
operations have an inverse, or opposite, operation. Subtraction is the opposite
of addition, division is the inverse of multiplication, and so on. Squaring,
which we learned about in a previous lesson (exponents),
has an inverse too, called "finding the square root." Remember, the
square of a number is that number times itself. The perfect squares are the
squares of the whole numbers: 1, 4, 9, 16, 25, 36, 49, 64, 81, 100 … </span>
The square root
of a number, n, written
<span>
is the number that gives n when multiplied by itself. For example,</span>
<span>because
10 x 10 = 100</span>
Examples
Here are the
square roots of all the perfect squares from 1 to 100.
Finding square
roots of of numbers that aren't perfect squares without a calculator
1. Estimate
- first, get as close as you can by finding two perfect square roots your
number is between.
2. Divide -
divide your number by one of those square roots.
3. Average -
take the average of the result of step 2 and the root.
<span>4. Use the result
of step 3 to repeat steps 2 and 3 until you have a number that is accurate
enough for you.
</span>
Example:
Calculate the square root of 10 ()
to 2 decimal places.
<span>1. Find
the two perfect square numbers it lies between.
</span>
<span><span>Solution:
</span><span>32
= 9 and 42 = 16, so
lies between 3 and 4.</span></span>
<span>2. Divide
10 by 3. 10/3 = 3.33 (you can round off your answer)</span>
<span>3. Average
3.33 and 3. (3.33 + 3)/2 = 3.1667</span>
<span>Repeat step
2: 10/3.1667 = 3.1579</span><span>Repeat step 3: Average 3.1579 and 3.1667. (3.1579 + 3.1667)/2 = 3.1623</span>
Try the answer
--> Is 3.1623 squared equal to 10? 3.1623 x 3.1623 = 10.0001
If this is accurate
enough for you, you can stop! Otherwise, you can repeat steps 2 and 3.
<span>Note:
There are a number of ways to calculate square roots without a calculator.
This is only one of them.</span>
<span><span>
</span>
</span>
<span>
<span />Example:
Calculate the square root of 10 ()
to 2 decimal places.
<span>1.
Find the two perfect square numbers it lies between.
</span>
<span><span>Solution:
</span><span>32
= 9 and 42 = 16, so
lies between 3 and 4.</span></span>
<span>2.
Divide 10 by 3. 10/3 = 3.33 (you can round off your answer)</span>
<span>3.
Average 3.33 and 3. (3.33 + 3)/2 = 3.1667</span>
<span>Repeat
step 2: 10/3.1667 = 3.1579
Repeat step 3: Average 3.1579 and 3.1667. (3.1579 + 3.1667)/2 = 3.1623</span>
<span>Try
the answer --> Is 3.1623 squared equal to 10? 3.1623 x 3.1623 =
10.0001</span>
If
this is accurate enough for you, you can stop! Otherwise, you can repeat steps
2 and 3.
</span>
<span>
<span><span>
<span> </span></span></span></span>
