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-Dominant- [34]
3 years ago
11

I am the number the divided the dividend

Mathematics
2 answers:
Lostsunrise [7]3 years ago
6 0
Oh My God what are you trying to talk about in this question
Sindrei [870]3 years ago
6 0
Wait what do you mean
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What did I do wrong, it says I'm wrong
Alisiya [41]

Answer:

This is not a function.

Step-by-step explanation:

Note, that set A contains 3 elements that only map to 2 elements in set B.  A function would require that each element of set A to match to only one element of set B.

Since set B contains an element with no mapping to an element in set A, this does not represent a function.

7 0
3 years ago
The hypotenuse of a right triangle is 89 meters long. One leg of the triangle is 39 meters long. What is the length of the other
Hitman42 [59]
A²+b²=c²
39²+b²=89²
1521+b²=7921
subtract 1521 from both sides
b²=6400
so then you square both sides
√6400
80
4 0
4 years ago
3x + 2 = x + 4(x+2) I really need help
luda_lava [24]

Answer:

x=-3

Step-by-step explanation:

3x+2=x+4x+8

3x+2=5x+8

-2x+2=8

-2x=6

x=-3

5 0
4 years ago
Read 2 more answers
Evaluate the function for the given domain. f(1) = -2x + 1
madam [21]
ANSWER -

-1


EXPLANATION - any expression multiplied by 1 remains the same
6 0
3 years ago
A biologist is studying the growth of a particular species of algae. She writes the fall inclusion to show the radius of the alg
horrorfan [7]

Answer:

Part A)

A reasonable domain to plot the growth function is:

0\leq d \leq 12

Part B)

The <em>y-</em>intercept represents that when the biologist started her study, the radius of the algae was five millimeters.

Part C)

The average rate of change from <em>d</em> = 4 to <em>d</em> = 11 was about 0.11. This means that from the 4th day to the 11th, the radius of the algae grew, on average, at a rate of 0.11 mm per day.

Step-by-step explanation:

The radius of the algae f(d) in millimeters after <em>d</em> days is given by the function:

f(d)=5(1.02)^d

Part A)

We know that the radius of the algae was approximately 6.34 mm when the biologist concluded her study. To find the reasonable domain, we can substitute 6.34 for f(d) and solve for <em>d</em>. Therefore:

6.34=5(1.02)^d

Divide both sides by five:

(1.02)^d=1.268

Take the log of both sides with base 1.02:

\displaystyle d=\log_{1.02}1.268

Using the Change of Base Property, evaluate for <em>d: </em>

<em />\displaystyle d=\frac{\log 1.268}{\log 1.02}=11.9903...\approx 12<em />

So, the biologist concluded her study after 12 days.

Therefore, a reasonable domain to plot the growth function is:

0\leq d\leq 12

Part 2)

The <em>y-</em>intercept of the function is when <em>d</em> = 0. Find the <em>y-</em>intercept:

f(0)=5(1.02)^{(0)}=5(1)=5

Since <em>d</em> represent the amount of days after the study had begun, the <em>y-</em>intercept represents the radius of the algae on the initial day.

So, when the biologist started her study, the radius of the algae was five millimeters.

Part 3)

To find the average rate of change for a nonlinear function, we find the slope between the two endpoints on the interval.

We want to find the average rate of change of f(d) from <em>d</em> = 4 to <em>d</em> = 11.

Find the endpoints:

f(4)=5.4121...\text{ and } f(11)=6.2168...

And find the slope between them:

\displaystyle m=\frac{f(11)-f(4)}{11-4}=0.1149...\approx 0.11

Since f(d) measures millimeters and <em>d</em> measures days, this tells us that, on average, the radius of the algae grew by about 0.11 mm per day from the 4th day to the 11th day.

5 0
3 years ago
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