What did I do wrong, it says I'm wrong

Mathematics

1 answer:

Alisiya [41]3 years ago

7 0

Answer:

This is not a function.

Step-by-step explanation:

Note, that set A contains 3 elements that only map to 2 elements in set B. A function would require that each element of set A to match to only one element of set B.

Since set B contains an element with no mapping to an element in set A, this does not represent a function.

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ruslelena [56]

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Step-by-step explanation:

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MrRa [10]

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Find the value of tan(sin^-1(1/2))

suter [353]

If you know that $\sin\dfrac\pi3=\dfrac12$ , then you know right away

$\tan\left(\sin^{-1}\dfrac12\right)=\tan\dfrac\pi3=\dfrac1{\sqrt}3=\dfrac{\sqrt3}3$

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Otherwise, you can derive the same result. Let $\theta=\sin^{-1}\dfrac12$ , so that $\sin\theta=\dfrac12$ . $\sin^{-1}$ is bounded, so we know $-\dfrac\pi2\le\theta\le\dfrac\pi2$ . For these values of $\theta$ , we always have $\cos\theta\ge0$ .