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AnnyKZ [126]
3 years ago
5

What did I do wrong, it says I'm wrong

Mathematics
1 answer:
Alisiya [41]3 years ago
7 0

Answer:

This is not a function.

Step-by-step explanation:

Note, that set A contains 3 elements that only map to 2 elements in set B.  A function would require that each element of set A to match to only one element of set B.

Since set B contains an element with no mapping to an element in set A, this does not represent a function.

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Which ratio forms a proportion with 7/14
Mazyrski [523]

Answer:

7 : 14, or simplified, 1 : 2

Step-by-step explanation:

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3 years ago
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The value of a car bought new for $28900 decreases 15% each year. Identify the function for the value of the car. Does the funct
Eva8 [605]

Answer:

<u>V (t) = 28,900 - 4,335t</u>

<u>The function clearly represent a decay</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Value of the car = $ 28,900

Annual depreciation = 15% = 0.15

2. Identify the function for the value of the car. Does the function represent growth or decay?

Let y represent the value of the car after t years of utilization, let p the price of the car and d, the annual depreciation, therefore:

V (t) = p - (d * t * p)

Replacing with the values we know:

V (t) = 28,900 - (0.15 * t * 28.900)

V (t) = 28,900 - (0.15 * t * 28.900)

<u>V (t) = 28,900 - 4,335t</u>

<u>The function clearly represent a decay.</u>

8 0
3 years ago
Q6. (15 points) IQ examination scores of 500 members of a club are normally distributed with mean of 165 and SD of 15.
melamori03 [73]

Answer:

a) 0.8413

b) 421

c) P_{95} = 189.675

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 165

Standard Deviation, σ = 15

We are given that the distribution of  IQ examination scores is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(IQ scores at most 180)

P(x < 180)

P( x < 180) = P( z < \displaystyle\frac{180 - 165}{15}) = P(z < 1)

Calculation the value from standard normal z table, we have,  

P(x < 180) = 0.8413 = 84.13\%

b) Number of the members of the club have IQ scores at most 180

n = 500

\text{Members} = n\times \text{P(IQ scores at most 180)}\\= 500\times 0.8413\\=420.65 \approc 421

c) P(X< x) = 0.95

We have to find the value of x such that the probability is 0.95

P( X < x) = P( z < \displaystyle\frac{x - 165}{15})=0.95  

Calculation the value from standard normal z table, we have,  

P(z < 1.645) = 0.95

\displaystyle\frac{x - 165}{15} = 1.645\\\\x = 189.675  

P_{95} = 189.675

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