First lets see the pythagorean identities
![sin^2 \Theta + cos^2 \Theta =1](https://tex.z-dn.net/?f=%20sin%5E2%20%5CTheta%20%2B%20cos%5E2%20%5CTheta%20%3D1%20)
So if we have to solve for sin theta , first we move cos theta to left side and then take square root to both sides, that is
![sin^2 \Theta = 1-cos^2 \Theta => sin \theta = \pm \sqrt{1-cos^2 \Theta}](https://tex.z-dn.net/?f=%20sin%5E2%20%5CTheta%20%3D%201-cos%5E2%20%5CTheta%20%3D%3E%20sin%20%5Ctheta%20%3D%20%5Cpm%20%5Csqrt%7B1-cos%5E2%20%5CTheta%7D%20)
Now we need to check the sign of sin theta
First we have to remember the sign of sin, cos , tan in the quadrants. In first quadrant , all are positive. In second quadrant, only sin and cosine are positive. In third quadrant , only tan and cot are positive and in the last quadrant , only cos and sec are positive.
So if theta is in second quadrant, then we have to positive sign but if theta is in third or fourth quadrant, then we have to use negative sign .
Answer:
the second one is correct
Step-by-step explanation:
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Answer:
The answer is- D
Step-by-step explanation:
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Draw a scalene triangle for the problem that is what is would be
Answer: The angles are 67.5°, 22.5° and 90°.
Step-by-step explanation:
It should be noted that a straight angle is always equal to 180°.
The straight angle is split in the ratio 3:1:4.
The measure of each angle will be:
a. = 3/(3+1+4) × 180°
= 3/8 × 180°
= 67.5°
b. 1/8 × 180° = 22.5°
c. 4/8 × 180° = 90°
The angles are 67.5°, 22.5° and 90°.