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statuscvo [17]
3 years ago
5

Kate is going to the fair with three of her friends. It will cost $5.00 to get in and an additional $2 per ride. Create an equat

ion to represent the cost for the whole group and then use the distributive property to expand the expression and solve the problem.
Mathematics
1 answer:
sladkih [1.3K]3 years ago
5 0

Answer:

10y + 3x + 10 + x -2y 3x – y + 4x + 6 – 2y factor 6a + 3          i think this might be right.

Step-by-step explanation:

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If Moses has an account balance of 19 dollars and Miles has an account balance of -19 dollars, how much
uranmaximum [27]

Answer:

zero dollars

Step-by-step explanation:

19+ (-19) simplifies to 19-19

19-19 equals 0

5 0
4 years ago
CAN SOMEONE HELL WITH THIS WILL GIVE 5 STARS
In-s [12.5K]

Answer:

<em>Thus both answers are: Positive infinity</em>

Step-by-step explanation:

<u>The Absolute Value</u>

It's the positive magnitude of a number, regardless of its sign, or zero if the number is zero.

Some examples of absolute values are:

\mid 4 \mid =4

\mid -4 \mid =4

\mid 0 \mid =0

\mid -107.5 \mid =107.5

We have the function:

g(x)=4\mid x-2\mid -3

As x approaches negative infinity, the absolute value approaches positive infinity, and the whole expression approaches positive infinity.

As x approaches positive infinity, the absolute value approaches positive infinity, and the whole expression approaches positive infinity.

Thus both answers are: Positive infinity

7 0
3 years ago
What is the slope of line<br> 4x+6y=24
Varvara68 [4.7K]
Y=mx+b
m is the slope
you need to get y on one side and all other numbers on the other
so here's the easiest way to do it:
just kinda take 4x (which is a positive number) and move it to the other side and change the sign. so then it turns into 6y=-4x+24 and then you divide both sides by 6 so then you get y=-4/6x+4 (4 over 6 like a fraction)
-4/6 is the slope
3 0
3 years ago
Find the absolute maximum and minimum values of f on the set D. f(x,y)=2x^3+y^4, D={(x,y) | x^2+y^2&lt;=1}.
castortr0y [4]

Answer:

absolute maximum is f(1, 0) = 2 and the absolute minimum is f(−1, 0) = −2.

Step-by-step explanation:

We compute,

$ f_x = 6x^2, f_y=4y^3 $

Hence, $ f_x = f_y = 0 $  if and only if (x,y) = (0,0)

This is unique critical point of D. The boundary equation is given by

$ x^2+y^2=1$

Hence, the top half of the boundary is,

$ T = \{ x, \sqrt{1-x^2} : -1 \leq x \leq 1\}

On T we have, $ f(x, \sqrt{1-x^2} = 2x^3 +(1-x^2)^2 = x^4 +2x^3-2x^2+1  \text{ for}\ -1 \leq x \leq 1$

We compute

$ \frac{d}{dx}(f(x, \sqrt{1-x^2}))= 4x^3+6x^2-4x = 2x(2x^2+3x-2)=2x(2x-1)(x+2)=0$

0 if and  only if x=0, x= 1/2 or x = -2.

We disregard  $ x = -2 \notin [-1,1]$

Hence, the critical points on T are (0,1) and $(\frac{1}{2}, \sqrt{1-(\frac{1}{2})^2}=\frac{\sqrt3}{2})$

On the bottom half, B, we have

$ f(x, \sqrt{1-x^2})= f(x,-\sqrt{1-x^2})$

Therefore, the critical points on B are (0,-1) and $( 1/2, -\sqrt3/2)  

It remains to  evaluate f(x, y) at the points $ (0,0), (0 \pm1), (1/2, \pm \sqrt3/2) \text{ and}\  (\pm1, 0)$ .

We should consider  latter two points, $(\pm1,0)$, since they are the boundary points for the T and also  B. We compute $ f(0,0)=0, \ \f(0 \pm1)=1, \ \ f(0, \pm \sqrt3/2)=9/16, \ \ f(1,0 )= 2 \text{ and}\ \ f(-1,0)= -2 $

We conclude that the  absolute maximum = f(1, 0) = 2

And the absolute minimum = f(−1, 0) = −2.

6 0
3 years ago
Can you Simplify 55/100?
Butoxors [25]
11/20
55 divided by 5 equals 11. 
100 divided by 5 equals 20
4 0
3 years ago
Read 2 more answers
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