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Sever21 [200]
3 years ago
15

What is 8/10 divided by 1 5/6

Mathematics
2 answers:
Verdich [7]3 years ago
6 0
Its going to be 55/24
sveta [45]3 years ago
5 0
1st change 1 5/6 into a mixed number:
1 5/6 = 11/6

New problem:
8/10 divided by 11/6

to divide fractions you turn the 1st fraction upside down and then change the division sign to a multiplication sign:

8/10 / 11/6
10/8 * 11/6
=55/24 or 1 7/24
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Given f(x) = 3x^3+ kx – 11, and x – 1 is a factor of f(x), then what is the value<br> of k?
STatiana [176]

let's recall the remainder theorem.

we know that (x-1) is a factor, that means x -1 = 0 or x = 1.

since we know that (x-1) is a factor, then dividing the polynomial by it will give us a remainder of 0, which correlates with saying that f(1) = 0, in this case, so we can simply plug in "1" as the argument, knowing it gives 0.

f(x)=3x^3+kx-11\\\\[-0.35em]~\dotfill\\\\\stackrel{0}{f(1)}=3(1)^3+k(1)-11\implies \stackrel{f(1)}{0}=3+k-11\implies 0=-8+k\implies 8=k

7 0
2 years ago
What value of x is in the solution set of 9(2x + 1) &lt; 9x - 18? <br> -4<br> -3<br> -2<br> -1
Anastaziya [24]

Answer:

The only possible answer that is correct is the first one, x = -4.

Step-by-step explanation:

Simplify the given inequality as much as possible, and then substitute each of the given x values one by one to determine which is in the solution set.

9(2x + 1) < 9x - 18 becomes 18x + 9 < 9x - 18, which, if reduced by dividing all four terms by 9, becomes 2x + 1 < x - 2.

Simplifying further, we get x < - 3.  The only possible answer that is correct is the first one, x = -4.  -4 < -3 is true.

8 0
3 years ago
Read 2 more answers
An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
3 years ago
On a test, you earn 92% of the possible points by correctly answering 6 five-point questions and 8 two-point questions. How many
olya-2409 [2.1K]

Step-by-step explanation:

(6×5)+(8×2)=46

92℅=46points

100℅=x

criss cross

<u>92℅x=46</u>

<u>9</u><u>2</u><u>℅</u><u>.</u><u> </u> 92℅

and this is the answer

8 0
3 years ago
Read 2 more answers
At a game booth, a student gets a box of candy as the prize for winning a game. The boxes come in four colors: white, red, green
Rainbow [258]
I think the answer is D) 8 over 32 multiplied by 7 over 31
Hopefully that helped! :) 
4 0
3 years ago
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