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4 years ago

Identify the range of the function shown in the graph

Mathematics

2 answers:

Setler [38]4 years ago

4 0

<h2>Answer:</h2>

The range of the function as is shown in the given graph is:

Option: C

C. 0 ≤ y ≤ 5

<h2>Step-by-step explanation:</h2>

We know that the domain of the function is the set of all the real values i.e. set of all the x-values for which a function is defined.

The range of a function is the set of all the real values which are attained by the function i.e. it is the set of all the values which the dependent variable i.e. y receives on all the possible domain values.

The function is defined between -5 and 5 inclusive.

i.e. Domain is: -5≤ x ≤ 5

By looking at the graph of the function we see that the function receives the values above the x-axis but it does not receive any value above 5

Hence, the range of the function is:

0 ≤ y ≤ 5

Scrat [10]4 years ago

3 0

<u>The answer to your question:</u> -5 $\leq$ y $\leq$ 5

The reason behind this is because -5 is the farthest to the left and 5 is farthest to the right of the ranges or y.

<em>Hope this helps! :) from peachimin</em>

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Then, the AVR is:

$AVR = \frac{18-(-2)}{3-(-2)}$

$AVR = \frac{18+2}{3+2}$

$AVR = \frac{20}{5}$

$AVR = 4$

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Evaluating for x =4:

$f (4) = 3 (4) - 8\\f (4) = 12 - 8\\f (4) = 4$

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Then, the AVR is:

$AVR = \frac{7-4}{5-4}$

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Then, the AVR is:

$AVR = \frac{8-15}{4-(-3)}$

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$AVR = \frac{-4+4}{1+1}$

$AVR = \frac{0}{2}$

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Answer:

from the greatest to the least value based on the average rate of change in the specified interval:

f(x) = x^2 + 3x interval: [-2, 3]

f(x) = 3x - 8 interval: [4, 5]

f(x) = x^2 - 5 interval: [-1, 1]

f(x) = x^2 - 2x interval: [-3, 4]

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