A + b = 15 ..... eq 1
a – b = 12 ...... eq 2
So a = 15 – b
Substitute in eq 2 :
15 – b – b = 12
15 – 2b = 12
–2b = 12 – 15
b = 1.5
So a = 15 – 3/2 = 13.5
4ab = 4 x 13.5 x 1.5 = 81
Answer:
C)
Step-by-step explanation:
As it is 60 degree, and the whole circle is 360 degree, so we need to find 1/6 of the circumference of a circle, as C = 2*pi*r = 2*pi*3 = 6pi and 1/6 of it is pi.
<u>Answer:</u>
Range of this relation = -3, 2
<u>Step-by-step explanation:</u>
We are given the following relation and we are to find its range:

The set of all the possible dependent values a relation can produce from its values of domain are called its range. In simple words, it is the list of all possible inputs (without repeating any numbers).
Therefore, the range of this relation is: -3, 2
Solution: Let x be the height of a student in Marta's class.
The mean height of 18 students in Marta's class is 60 inches
We know that:




Therefore, the total measure of all 18 student's heights is 1080 inches
Answer:adult=75
Students = 200
Children=75
Step-by-step explanation:
Let x= adult tickets, y=students, z=child
x+y+z =350
Since x=z
y+2z= 350 -----------1
20x +12y + 10z = 4650
Since y=z
12y +30z = 4650 --------2
Using elimination method to solve eqn 1&2
Multiply eqn 1 by 12
12y + 24z = 4200
12y +30z = 4650
Subtract equ 2 from 1
-6z =-450
z=75, x = 75
y=350 -(75+75)
y= 200 tickets