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Firlakuza [10]
3 years ago
5

Sort the cities from closest to farthest from sea level. Please help me

Mathematics
1 answer:
dimaraw [331]3 years ago
5 0
I think
J,BB,S

(I shortened name to letter)
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Suppose that 70% of the orders on a particular website are shipped to the person who is making the order and the remaining 30% a
Lera25 [3.4K]

Answer:

0.18 ; 0.1875 ; No

Step-by-step explanation:

Let:

Person making the order = P

Other person = O

Gift wrapping = w

P(p) = 0.7 ; P(O) = 0.3 ; p(w|O) = 0.60 ; P(w|P) = 0.10

What is the probability that a randomly selected order will be a gift wrapped and sent to a person other than the person making the order?

Using the relation :

P(W|O) = P(WnO) / P(O)

P(WnO) = P(W|O) * P(O)

P(WnO) = 0.60 * 0.3 = 0.18

b. What is the probability that a randomly selected order will be gift wrapped?

P(W) = P(W|O) * P(O) + P(W|P) * P(P)

P(W) = (0.60 * 0.3) + (0.1 * 0.7)

P(W) = 0.18 + 0.07

P(W) = 0.1875

c. Is gift wrapping independent of the destination of the gifts? Justify your response statistically

No.

For independent events the occurrence of A does not impact the occurrence if the other.

4 0
3 years ago
Seven times the difference of a number and 1
weeeeeb [17]
Describe that better
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For the function y = 7-3x, what is<br> ordered pair for x=5?
Strike441 [17]

(5,0) if there is no y then it is a 0

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3 years ago
Type the correct answer in each box. Use numerals instead of words.
lubasha [3.4K]

Answer:

System A has 4 real solutions.

System B has 0 real solutions.

System C has 2 real solutions

Step-by-step explanation:

System A:

x^2 + y^2 = 17   eq(1)

y = -1/2x            eq(2)

Putting value of y in eq(1)

x^2 +(-1/2x)^2 = 17

x^2 + 1/4x^2 = 17

5x^2/4 -17 =0

Using quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a = 5/4, b =0 and c = -17

x=\frac{-(0)\pm\sqrt{(0)^2-4(5/4)(-17)}}{2(5/4)}\\x=\frac{0\pm\sqrt{85}}{5/2}\\x=\frac{\pm\sqrt{85}}{5/2}\\x=\frac{\pm2\sqrt{85}}{5}

Finding value of y:

y = -1/2x

y=-1/2(\frac{\pm2\sqrt{85}}{5})

y=\frac{\pm\sqrt{85}}{5}

System A has 4 real solutions.

System B

y = x^2 -7x + 10    eq(1)

y = -6x + 5            eq(2)

Putting value of y of eq(2) in eq(1)

-6x + 5 = x^2 -7x + 10

=> x^2 -7x +6x +10 -5 = 0

x^2 -x +5 = 0

Using quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a= 1, b =-1 and c =5

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(1)(5)}}{2(1)}\\x=\frac{1\pm\sqrt{1-20}}{2}\\x=\frac{1\pm\sqrt{-19}}{2}\\x=\frac{1\pm\sqrt{19}i}{2}

Finding value of y:

y = -6x + 5

y = -6(\frac{1\pm\sqrt{19}i}{2})+5

Since terms containing i are complex numbers, so System B has no real solutions.

System B has 0 real solutions.

System C

y = -2x^2 + 9    eq(1)

8x - y = -17        eq(2)

Putting value of y in eq(2)

8x - (-2x^2+9) = -17

8x +2x^2-9 +17 = 0

2x^2 + 8x + 8 = 0

2x^2 +4x + 4x + 8 = 0

2x (x+2) +4 (x+2) = 0

(x+2)(2x+4) =0

x+2 = 0 and 2x + 4 =0

x = -2 and 2x = -4

x =-2 and x = -2

So, x = -2

Now, finding value of y:

8x - y = -17    

8(-2) - y = -17    

-16 -y = -17

-y = -17 + 16

-y = -1

y = 1

So, x= -2 and y = 1

System C has 2 real solutions

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3 years ago
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Evaluate 3a+15+bc−6, when a=7, b=3, and c=15.<br><br> Enter your answer in the box.
melamori03 [73]
I think it's 75.
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5 0
3 years ago
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