Answer:
<em>5.48</em>
<em></em>
Step-by-step explanation:
Given length of three strings:
![\text{Length of first string}, L_1=7.68\ inches\\\text{Length of second string}, L_2=3.9\ inches\\\text{Length of third string}, L_3=2.2\ inches](https://tex.z-dn.net/?f=%5Ctext%7BLength%20of%20first%20string%7D%2C%20L_1%3D7.68%5C%20inches%5C%5C%5Ctext%7BLength%20of%20second%20string%7D%2C%20L_2%3D3.9%5C%20inches%5C%5C%5Ctext%7BLength%20of%20third%20string%7D%2C%20L_3%3D2.2%5C%20inches)
To find:
The difference in length between the longest and the shortest string?
Solution:
First of all, let us compare the given three decimal numbers.
We check the number before decimal first of all.
We can see that the numbers are 7, 3, and 2.
7 being the largest
is the longest string.
2 being the smallest
is the shortest string.
So, the difference is:
![L_1-L_3=7.68-2.2\\\Rightarrow \bold{L_1-L_3=5.48 }](https://tex.z-dn.net/?f=L_1-L_3%3D7.68-2.2%5C%5C%5CRightarrow%20%5Cbold%7BL_1-L_3%3D5.48%20%7D)
So, the answer is <em>5.48.</em>
Hi there!
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I believe your answer is:
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Here’s why:
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![\boxed{6^5*6^2}\\\\\rightarrow \text{Recall exponent rule: } a^x*a^y=a^{x+y}\\\\\\rightarrow 6^5 * 6^2\\\\\rightarrow 6^{5+2}\\\\\rightarrow \boxed{6^7}\\\\\\\text{\textbf{None} of the given options are correct.}](https://tex.z-dn.net/?f=%5Cboxed%7B6%5E5%2A6%5E2%7D%5C%5C%5C%5C%5Crightarrow%20%5Ctext%7BRecall%20exponent%20rule%3A%20%7D%20a%5Ex%2Aa%5Ey%3Da%5E%7Bx%2By%7D%5C%5C%5C%5C%5C%5Crightarrow%206%5E5%20%2A%206%5E2%5C%5C%5C%5C%5Crightarrow%206%5E%7B5%2B2%7D%5C%5C%5C%5C%5Crightarrow%20%5Cboxed%7B6%5E7%7D%5C%5C%5C%5C%5C%5C%5Ctext%7B%5Ctextbf%7BNone%7D%20of%20the%20given%20options%20are%20correct.%7D)
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Hope this helps you. I apologize if it’s incorrect.
To solve this problem you must apply the proccedure shown below:
1. You have the following logarithm:
<span>log(2)n=4
2. Therefore, you con rewrite it as below:
loga(b)=logb/loa
</span>
3. Therefore, you have:
log(2)n=4⇒log(n)/log(2)=4
4. Then, you obtain:
log(n)=4log(2)
5. Therefore, as you can see, the answer for the exercise shown above is the last option, which is:
log(n)=4log(2)
Answer:
60°
Step-by-step explanation:
There are a couple of ways to think about this.
a) If we rearrange the figure so both angle vertices are in the same place, then the marked angles would overlap. The amount of that overlap is ...
125° +115° -180° = 60°
That is, the smaller angle between the diagonal lines has a measure of 60°. The measure of i is 60°.
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b) If we extend the lower horizontal line to the left, as in the attached figure, we see that the external angle of the resulting triangle is an alternate interior angle that is congruent to the one marked 125°. The remote interior angles of the triangle with respect to that angle are "i" and (180° -115°) = 65°.
The exterior angle is the sum of the remote interior angles, so we have ...
125° = i + (180° -115°)
i = 125° +115° -180° = 60° . . . . as above
Answer:
Option A
Step-by-step explanation:
the area of the parallelogram is 22.05