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Zanzabum
3 years ago
11

This proportion can be solved to find the unknown length, x, in the smaller triangle. 124=6x use the drop-down menus to complete

the solution below.

Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
7 0

i got this right on im

Elodia [21]3 years ago
4 0
The unknown X equals 20.66.
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Which situation could be represented by linear function
ddd [48]

Answer:

d. The amount of people in a town increase by 50 people every 5 years.

Step-by-step explanation:

this is because if you were to graph it, it would be a straight line while the other options the line would be curved.

8 0
3 years ago
The students at Woodward Elementary voted for a school mascot. The falcon won with 5/8 of the votes and the eagle came second wi
Greeley [361]

Answer:

178.67

Step-by-step explanation:

One third written as a fraction is 1/3. You can also write it as a decimal by simply dividing 1 by 3 which is 0.33.

If you multiply 0.33 with 536 you will see that you will end up with the same answer as above.

You may also find it useful to know that if you multiply 0.33 with 100 you get 33.33. Which means that our answer of 178.67 is 33.33 percent of 536.

4 0
3 years ago
Consider the linear equation y=4x-7 find the value of y that makes the given ordered pair a solution to the equation (3, y) Y=
olchik [2.2K]
Y = 4x - 7 is a line with a slope of 4 and y-intercept of -7.

plug in any X value, for example 1 and you get the following

y = 4(1) - 7

y = -3

(1,-3) is a point that satisfies the equation y = 4x - 7
3 0
3 years ago
Which of the following is the complete factorization of 10x - 3 - 3x2? -(3x + 1)(x - 3) -(3x - 1)(x - 3) (3x - 1)(x + 3)
qaws [65]

Answer:

=-\left(3x-1\right)\left(x-3\right)

Step-by-step explanation:

10x-3-3x^2\\\mathrm{Factor\:out\:common\:term\:}-1\\=-\left(3x^2-10x+3\right)\\\mathrm{Factor}\:3x^2-10x+3:\quad \left(3x-1\right)\left(x-3\right)\\3x^2-10x+3\\\mathrm{Write\:in\:the\:standard\:form}\:ax^2+bx+c\\=3x^2-10x+3\\\mathrm{Break\:the\:expression\:into\:groups}\\=\left(3x^2-x\right)+\left(-9x+3\right)\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}3x^2-x\mathrm{:\quad }x\left(3x-1\right)\\3x^2-x\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c\\x^2=xx\\=3xx-x

\mathrm{Factor\:out\:common\:term\:}x\\=x\left(3x-1\right)\\\mathrm{Factor\:out\:}-3\mathrm{\:from\:}-9x+3\mathrm{:\quad }-3\left(3x-1\right)\\-9x+3\\\mathrm{Rewrite\:}9\mathrm{\:as\:}3\cdot \:3\\=-3\cdot \:3x+3\\\mathrm{Factor\:out\:common\:term\:}-3\\=-3\left(3x-1\right)\\=x\left(3x-1\right)-3\left(3x-1\right)\\\mathrm{Factor\:out\:common\:term\:}3x-1\\=\left(3x-1\right)\left(x-3\right)\\=-\left(3x-1\right)\left(x-3\right)

5 0
4 years ago
Read 2 more answers
A 50-gal tank initially contains 20 gal of pure water. Salt- water solution containing 0.5 lb of salt for each gallon of water b
icang [17]

Answer:

x(15) = 21 lb

Step-by-step explanation:

Rate of change in volume of salt water solution = rate of volume incoming - rate of volume outgoing

                                dV/dt  = 4 - 2 =2gal/min

So, the equation for volume at cetain time t at given conditions and values becomes,

                                V(t) = 2t + V

                                V(t) = 2t + 20   gal-------------------euqation (1)

Rate of change in amount of salt = rate of salt in - rate of salt out

                                  dx/dt = {0.5*4} - {[x(t)/V(t)]*2}

                                  dx/dt = 2-2[(x(t))/(2t+20)]

                                  dx/dt = 2-[(x(t))/(v(t))] lb/min

Now, with integrating factor, we get

          exp[∫(1/(1+10))dt)] = t+10

the equation becomes

(t + 10)*x' + x = 2*(t+10)

((t+10)*x') = 2*(t+10)

(t+10)*x = t² + 20t + C

As x(0) = 0,

x(t) = (t²+20t)/(t+10)

x(15) = (15²+20*15)/(15+10)

x(15) = 21 lb

4 0
3 years ago
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