Answer:
3/5
Step-by-step explanation:
avg in A = 41
avg in B = 38
combined avg of A and B = 36
Let a = number of people in group A.
Let b = number of people in group B.
The total number of people = a + b.
The sum of all ages in group A is 41a.
The sum of all ages in group B is 36b.
The sum of all ages in the combined group A and B is 38(a + b).
41a + 36b = 38(a + b)
41a + 36b = 38a + 38b
3a = 2b
a/b = 2/3
a/b + 1 = 2/3 + 1
a/b + b/b = 2/3 + 3/3
(a + b)/b = 5/3
b/(a + b) = 3/5
Answer: You will have one and two sixth cups of nuts in all or 1 2/6 cups.
Step-by-step explanation: 1.) add the first two fractions. 1/6 + 1/6 = 2/6
2.) add the second fractions. 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 = 8/8 = 1
3.) add the whole number and fraction. 2/6 + 1 = 1 2/6.
Answer:
8
Step-by-step explanation:
That total is ...
(number of possibilities in each location)^(number of locations) = 2^3 = 8
The possible numbers are ...
444, 449, 494, 499
944, 949, 994, 999
There are 8 of them.
Answer:
Step-by-step explanation:
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by
T(x) = 160-0.05x^2
a. [0, 10]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
The average temperature
= (160 + 155)/2 = 157.5
b. [10, 40]
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (80 + 155)/2 = 117.5
c. [0, 40]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (160 + 80)/2 = 120
