Answer:
The mean of the sampling distribution of the sample proportions is 0.82 and the standard deviation is 0.0256.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For proportions, the mean is
and the standard deviation is 
In this problem, we have that:
.
So


The mean of the sampling distribution of the sample proportions is 0.82 and the standard deviation is 0.0256.
90 pb hope it helped ssdyacyd ja hcdke uvsk fideciscwtory264994972076159467577396257242
Answer:
2
Step-by-step explanation:
The first term is our fifrth and 13th is our 9th term in the new sequence. So each step has to be 2. 2 * 8 = 16
Our angle teta is:
teta = 3pi/4
since that is larger than pi/2 but less than pi that means that our angle lies in II quadrant (x negative y positive)
sin(3pi/4) = √2/2
cosine and tangent of that angle must be negative because of position of the angle.
cos(3pi/4) = -√2/2
tan(3pi/4) = -1
Area = l x w
Area =9 x 4.25
A = 48.25
A≈ 48 in²