You would divide them both my two to get 9/7
Answer:
for me it was d=3.2t+0.6
Step-by-step explanation:
but to find the part where they intersect its (0.75,3)
Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
Answer:
4 I guess..........not sure but my answer is 4
Answer:
x = 30
Step-by-step explanation:
1/2(x+6) = 18
Distribute
1/2 x + 3 = 18
Subtract 3 from each side
1/2x +3-3 = 18-3
1/2x = 15
Multiply each side by 2
1/2x*2 = 15*2
x = 30
