We have that
y=-3x²<span>+5x+11
we know that
the equation of the parabola in standard form can be expressed in one of the following two ways
y=ax</span>²+bx+c
<span>the parabola opens up if a is positive and opens down if a is negative
and
x=ay</span>²+by+c
the parabola opens right if a is positive and opens left if a is negative
<span>
in this problem
the equation is of the form
</span>y=ax²+bx+c<span>
a=-3
so
the parabola opens down
using a graph tool
see the attached figure
the vertex of a parabola is a maximum
the answer is</span>
the parabola opens down
Answer:
Your answer would be 13.2.
Two lines are perpendicular to the same line so they are parallel .
X= 4
Because I need to answer a question in order to answer other questions so your welcome.
Answer:
The numerical answer is 5
Please see the tape diagram evolution in the attached image
Step-by-step explanation:
Start by drawing three unit tapes, and divide each one of them in 5 equal parts since we need to be dividing the quantity 3 by 3/5 (denominator 5)
In the second step, join the three tapes in one long one maintaining the original divisions.
In the third step, select groups of 3 divisions (recall you need to divide by 3/5) which will identify in your tape how many of these 3/5 groups you have.
Finally count the number of 3/5 groups you found in the collection of the three original tapes placed together. You should count a total of 5 of these 3/5 groups.
5 then tells you what is the quotient of 3 divided in 3/5