Ask question

Ask question

All categories

3 years ago

10

sadie finished her math test 16 minutes less than 3 times the amount of time it took her friend laura to finish. if their combin

ed time was 68 minutes how long did it take sadie

1 answer:

Yuliya22 [10]3 years ago

3 0

47 minutes because 21 times 3 is 63 and 63 minus 16 is 47. Also 47 plus 21 is equal to 68.

You might be interested in

What is the answer to -6<21

adell [148]

Answer:

Step-by-step explanation:

I've already answered this question.

8 0

3 years ago

Solve the literal equation for y. 2x-4y=20

Phoenix [80]

2x -4y=20
-4y=-2x+20
Y= 1/2x - 5 that’s the answer

3 0

4 years ago

Read 2 more answers

A NASA mathematician used a system of equations to determine the point in space where a satellite crossed paths with a massive p

nikitadnepr [17]

Answer:

Option D.

3 equations with 3 variables

Step-by-step explanation:

The coordinates of a point in space must necessarily have 3 components. One to describe the distance on the x axis, another to describe the distance on the y axis to the point, and a third to describe the distance on the z axis.

If we have three variables, then 3 equations are needed to solve the system. With less than 3 equations it would be impossible to solver the system.

Therefore the correct answer is option D.

3 equations with 3 variables

8 0

3 years ago

A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate

neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

$C-2=\frac{1}{11}*(C+D-2)...(1)$

We are also told if he instead added 4 glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

$C=\frac{1}{7}*(C+D+4)...(2)$

Upon substituting C's value from equation (2) in equation (1) we will get,

$\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)$

Let us have a common denominator on right side of equation.

$\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)$

$\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)$

Multiplying both sides of our equation by 7, we will get,

$7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)$

$C+D-10=\frac{7}{11}*(C+D-2)$

Multiplying both sides of our equation by 11, we will get,

$11*(C+D-10)=11*\frac{7}{11}*(C+D-2)$

$11*(C+D-10)=7*(C+D-2)$

$11C+11D-110=7C+7D-14$

$11C-7C+11D-7D=-14+110$

$4C+4D=96$

$4(C+D)=96$

$(C+D)=\frac{96}{4}$

$(C+D)=24$

Therefore, the total number of Munchkins in original box is 24.

3 0

3 years ago

V = ℓwh for ℓ. please help soon

erma4kov [3.2K]

Isolate the variable by dividing each side by factors that don't contain the variable.
l = v/wh

w
h

4 0

3 years ago