This relates to ur previous question....there were 85 innings last question and 130 walks + hits which gave a whip score of 1.53......so if he wants to lower his whip (without changing his walks or hits) to 1.3....
130 / (85 + x) = 1.3....multiply both sides by (85 + x)
130 = 1.3(85 + x)
130 = 110.50 + 1.3x
130 - 110.50 = 1.3x
19.5 = 1.3x
19.5 / 1.3 = x
15 = x
he would have to pitch 15 more innings without any walks or hits to reach a goal of 1.3 whip score. This is not a reasonable goal.....have u ever seen a baseball game where a pitcher pitched 15 innings without any walks or hits ? And since a game consists of 9 innings....he would be 3 innings short of 2 games (thats if they dont go into overtime), and he would have to pitch a no hitter....and that is highly unlikely.
Answer:
YES
NO
NO
Step-by-step explanation:
The given polynomial is: 
(x - a) is a factor of a polynomial iff x = a is a solution to the polynomial.
To check if (x - 5) is a factor of the polynomial f(x), we substitute x = 5 and check if it satisfies the equation.
∴ f(5) = 5³ + 4(5)² - 25(5) - 100
= 125 + 100 - 125 - 100
= 225 - 225
= 0
We see, x = 5 satisfies f(x). So, (x - 5) is a factor to the polynomial.
Now, to check (x + 2) is a factor.
i.e., to check x = - 2 satisfies f(x) or not.
f(-2) = (-2)³ + 4(-2)² - 25(-2) - 100
= -8 + 16 + 50 - 100
= -108 + 66
≠ 0
Therefore, (x + 2) is not a factor of f(x).
To check (x - 4) is a factor.
∴ f(4) = 4³ + 4(4)² - 25(4) - 100
= 64 + 64 - 100 - 100
= 128 - 200
≠ 0
Therefore, (x - 4) is not a factor of f(x).
For 2/5 cup, vanilla needed = 8 teaspoons
so, for 1 cup, it would be: 8 / 2/5
⇒8 × 5/2
⇒40/2
⇒20
In short, Your Answer would be 20 teaspoons
Hope this helps!
The slope is - 3/10
Y over x
Answer:
Number of rats : Food weight = 1 : 5
Step-by-step explanation:
Number of rats in the group = 9
Weight of food carried away by them = 45 kg
Ratio of the number of rats and food weight = 
= 
= 
= 
Therefore, Number of rats : Food weight = 1 : 5