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2 years ago

I NEED HELP WITH THIS ASAP

Mathematics

1 answer:

madreJ [45]2 years ago

3 0

Answer:

I think its AED19

Step-by-step explanation:

please give brainliest if correct

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Find the angle measure that makes the statement true. Sin ____° = Cos 37 °

Bingel [31]

$We\ know:\\\\\cos(90^o-\alpha)=\sin\alpha\\\\\cos37^o=\cos( 90^o-53^o)=\sin53^o$

8 0

3 years ago

Urgent answer please <br> Ax+ay+xa+ya

marin [14]

Answer:

Possible derivation:

d/dx(a x + a y(x) + x a + y(x) a)

Rewrite the expression: a x + a y(x) + x a + y(x) a = 2 a x + 2 a y(x):

= d/dx(2 a x + 2 a y(x))

Differentiate the sum term by term and factor out constants:

= 2 a (d/dx(x)) + 2 a (d/dx(y(x)))

The derivative of x is 1:

= 2 a (d/dx(y(x))) + 1 2 a

Using the chain rule, d/dx(y(x)) = (dy(u))/(du) (du)/(dx), where u = x and d/(du)(y(u)) = y'(u):

= 2 a + d/dx(x) y'(x) 2 a

The derivative of x is 1:

= 2 a + 1 2 a y'(x)

Simplify the expression:

= 2 a + 2 a y'(x)

Simplify the expression:

Answer: = 2 a

Step-by-step explanation:

8 0

3 years ago

If A = (0, 0) and B = (6, 3) what is the length of overline AB ?

Kaylis [27]

Answer:

A= (0,0) and B = (6,3)

We can find the length AB with the following formula:

$d = \sqrt{(x_B -x_A)^2 +(y_B -y_A)^2}$

And replacing we got:

$d = \sqrt{(6-0)^2 +(3-0)^2} = \sqrt{45}= 3\sqrt{5}$

So then the length AB would be $3\sqrt{5}$

Step-by-step explanation:

For this case we have the following two points:

A= (0,0) and B = (6,3)

We can find the length AB with the following formula:

$d = \sqrt{(x_B -x_A)^2 +(y_B -y_A)^2}$

And replacing we got:

$d = \sqrt{(6-0)^2 +(3-0)^2} = \sqrt{45}= 3\sqrt{5}$

So then the length AB would be $3\sqrt{5}$

7 0

3 years ago

How are the answers to problems 6,8,12, and 14 similar?how are they different?

Tasya [4]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

PLZ HELP ill GIVE BRAINIESt!!!!20 Points

shepuryov [24]

She made her mistake at the first step. To simplify a radical, you would find two numbers that multiply by each other to get your original number (under the radical) and have one of the number be a perfect square.

Her reasoning is wrong because 10*10 is not $\sqrt{50}$ . Had she been correct, her answer should have been able to be squared to equal $\sqrt{50}$

In other words, she should have done $\sqrt{25*2}= \sqrt{25} * \sqrt{2}=5 \sqrt{2}$
(We used 25 because 25 is a perfect square, 5*5=25).

:)

3 0

3 years ago