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nasty-shy [4]
3 years ago
12

Divide 20 chocolates between Adi and Suresh such that adi gets 60% while Suresh gets 40% of the chocolates

Mathematics
1 answer:
Eddi Din [679]3 years ago
6 0

Hello!

To find how much chocolate Adi and Suresh receives, you need to convert the percentage to a decimal, then you multiply that decimal by the total number of chocolates, which is 20.

To convert percentages to decimals, divide the percentage by 100, and remove the percentage.

60% / 100 = 0.60

20% / 100 = 0.20

Then, we multiply 0.60 and 0.20 by 20.

0.60 x 20 = 12

0.40 x 20 = 8

Therefore, Adi gets 12 chocolates and Suresh gets 8 chocolates.

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Answer:

\frac{92}{15}

Step-by-step explanation:

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this gives us

\frac{92}{15}

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Help please asap PLEASE TELL ME THE WORKING AS WELL.​
DanielleElmas [232]

Answer:

a = 9 / 7

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9 / - a + 15 = 8

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getting home from trick or treat celia and emma counted their candies. half of celias candies is equal to 2/3 of emmas candies.
blagie [28]

Candies with celias and emmas is 60 and 45 respectively.

<u>Solution:</u>

Given, Getting home from trick or treat celia and emma counted their candies.  Half of celias candies is equal to 2/3 of emmas candies.  

They had a total of 105 candies altogether.  

We have to find how many candies did each of them have.

Let the number of candies with celias be n, then number of candies with emma will be 105 – n.

Now according to given condition.

\begin{array}{l}{\frac{1}{2} \times \text { celias candies count }=\frac{2}{3} \times \text { emmas candies count }} \\\\ {\rightarrow \frac{1}{2} \times n=\frac{2}{3} \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 n=4(105-n)} \\\\ {\quad \rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n+4 n=420} \\\\ {\rightarrow 7 n=7 \times 60} \\\\ {\rightarrow n=60}\end{array}

Hence, candies with celias and emmas is 60 and 45 respectively.

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3 years ago
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