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Sliva [168]
3 years ago
6

Suppose individuals with a certain gene have a 0.70 probability of eventually contracting a certain disease. If 100 individuals

with the gene are randomly selected. The random variable describing the number of individuals who will contract the disease is:_______
Mathematics
1 answer:
Arturiano [62]3 years ago
6 0

Answer:

B(0.7, 100)

Step-by-step explanation:

Probability of contracting a certain disease = 0.70

No of individual randomly selected = 100

Contracting the disease is a positive/success in this case, hence

p = 0.7 and since there are 100 selection, the binomial distribution B(0.7, 100)

Hence, the The random variable describing the number of individuals who will contract the disease is B(0.7, 100) distribution.

And Mean = 0.7 x 100 = 70

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Answer: The range is y ≥ 3.

Step-by-step explanation:

When we have an equation:

y = f(x)

The range is the set of the possible values of y.

In this case, we have:

y = f(x) = 2*x^2 - 20*x + 53

This is a quadratic equation, and the leading coefficient is positive. This means that the arms of the graph will open upwards.

Then the minimum value of y will be the vale at the vertex.

We know that for a quadratic equation of the form:

a*x^2 + b*x + c

The vertex is at:

x = -b/2a

Then in this case, the vertex will be at:

x = -(-20)/(2*2) = 20/4 = 5

Then the smallest value of this function will be:

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This is the smallest value that y can take, and y can take any value greater than 3.

Then the range can be written as:

y ≥ 3.

4 0
3 years ago
P(x) Q(x) = R(x); if P(x)<br> 72 Am<br> R(x); if P(x)=x+2 and R(x) = x³ - 3x² - 6x-2, what is Q(x)?
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Answer:

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Joanna is driving 185 miles to visit her family. She drives 68 miles in the morning, stops for lunch, and then drives the rest o
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Step-by-step explanation:

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