Answer:
I am not sure, but I believe it is the last one. Sorry if it's not right.
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Answer:
a² + 16a - 612 = 0
Step-by-step explanation:
Here is the complete question :
The width of an extra large rectangle poster is 8 inches more than half its length. The area of this poster is 306 square inches
Write an equation in one variable that could be used to find the number of inches in the dimensions of this poster.
Area of a rectangle = length x width
Let length = a
width = 8 + 1/2a
Area = (8 + 1/2a) x a
306 = (8 + 1/2a) x a
multiply both sides of the equation by 2
612 = 16a + a²
a² + 16a - 612 = 0
the dimensions of the poster can be determined using quadratic formula
Answer:
x=1
Step-by-step explanation:
To solve, we need to get x by itself. To do this, preform the opposite of what is being done to the equation, and everything that is done to one side, must be done to the other.
5(2x-8)+15= -15
First, subtract 15 from both sides, since 15 is being added
5(2x-8)+15-15=-15-15
5(2x-8)=-30
Next, divide both sides by 5 since 5 is being multiplied
5(2x-8)/5= -30/5
2x-8= -6
Add 8 to both sides, since 8 is being subtracted
2x-8+8= -6+8
2x= 2
Divide both sides by 2, since 2 is being multiplied
2x/2= 2/2
x=1