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3 years ago

What is the value of x? 63 92 58 121

Mathematics

2 answers:

mojhsa [17]3 years ago

6 0

63 because it is the only answer that makes sense.

Bond [772]3 years ago

3 0

he right fo sho my young bois 63 is where its at

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⚠️A machine used 48% of its oil. What fraction of its oil did the machine

Alex777 [14]

Answer:

12/25

Step-by-step explanation:

48/100 simplifies to 24/50. 24/50 simplififes to 12/25.

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3 years ago

.) Find – 4.25 +2.5.

Arturiano [62]

The answer is -4 + 2 + -0.25 + 0.5.

3 0

3 years ago

Please I need help!!!!!

patriot [66]

Answer:

Solution given:

we have

f(x)=x²-9x-36

let

y=x²-9x-36

when

x=0

y=-36

when

y=0

0=x²-9x-36

x²-12x+3x-36=0

x(x-12)+3(x-12)=0

(x-12)(x+3)=0

either

x=12

x=-3

So,

x and y intercepts are (-3,0)(12,0) and 0,-36)

3 0

3 years ago

Please help me answer all parts of the question in the photo.

Vika [28.1K]

$6-4i\\3-6i+4i=3-2i\\3+4i-2+i=3-2+4i+i=1+5i$

5 0

3 years ago

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

$\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}$

7 0

3 years ago