The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using

Substitute the known values in the above equation

Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer:
Option C
Step-by-step explanation:
we have

step 1
Group terms that contain the same variable, and move the constant to the opposite side of the equation

step 2
Factor -6 leading coefficient'

step 3
Complete the square
Remember to balance the equation by adding the same constants to each side


step 4
Rewrite as perfect squares

simplify

Answer:
-4 +4 =0
Step-by-step explanation:
The sum of a number and its' additive inverse is 0
The additive inverse of -4 is 4
-4 +4 =0
Answer:yes
Step-by-step explanation:Bc I am right and right
Answer:
18
Step-by-step explanation:
12+24/4
12+6
18
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