How many solutions are in 6x+30+4x=10(x+3)

Mathematics

2 answers:

Jobisdone [24]3 years ago

8 0

First, let's simplify the equation.

$6x + 30 + 4x = 10(x + 3)$

Set up

$10x + 30 = 10(x + 3)$

Combine like terms

$10x + 30 = 10x + 30$

Apply the Distributive Property to the right hand side of the equation

$30 = 30$

Subtract $10x$ from both sides of the equation

Since the right and left sides of the equation are equal, we know that there must be an infinite number of solutions. This means that there is an infinite amount of values that we can substitute for $x$ for the equation to be true.

Andrews [41]3 years ago

3 0

Answer:

There is no solution for the equation.

See the explanation.

Step-by-step explanation:

Solve the equation :

Put x in one side and the other numbers in the other side.

You will get 10x - 10x = 30-30

= > which equals to 0=0

Whenever you get that, that means there is no solutions for the equation.

Hope this helps!

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