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pentagon [3]
3 years ago
9

What’s

Mathematics
1 answer:
Vadim26 [7]3 years ago
4 0

1.  1.8

2.  100

3.  103.1

4.  16

5. 281.1

6. 27.8

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50 points!!! Will mark brainliest
Murrr4er [49]

Answer:

x=20

Step-by-step explanation:

form a ratio

28:7

4:1

x:5

x=20

3 0
2 years ago
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nlexa [21]
I believe the answer is C, x-3.
4 0
3 years ago
Which linear function represents the line given by the point-slope equation y + 7 = –2/3(x + 6)?a. f(x) = –2/3x – 11b. f(x) = –2
Pavel [41]

Answer:

option C

y=\frac{-2}{3}x-11

Step-by-step explanation:

The point slope equation of a line is given by

y-y_1=m(x-x_1)

Where m is the slope and (x1,y1) is the point on the point

y + 7 =\frac{-2}{3}(x + 6)

We need to write the equation in y=mx+b form

multiply -2/3 inside the parenthesis

y + 7 =\frac{-2}{3}x-4

Subtract 7 from both sides

y=\frac{-2}{3}x-11

4 0
3 years ago
The functions f(x) = −(x − 1)2 5 and g(x) = (x 2)2 − 3 have been rewritten using the completing-the-square method. apply your kn
ale4655 [162]

The vertex of the function f(x) exists (1, 5), the vertex of the function g(x) exists (-2, -3), and the vertex of the function f(x) exists maximum and the vertex of the function g(x) exists minimum.

<h3>How to determine the vertex for each function is a minimum or a maximum? </h3>

Given:

$\mathrm{f}(\mathrm{x})=-(\mathrm{x}-1)^{2}+5$ and

$\mathrm{g}(\mathrm{x})=(\mathrm{x}-2)^{2}-3$

The generalized equation of a parabola in the vertex form exists

$y=a(x-h)^{2}+k

Vertex of the function f(x) exists (1, 5).

Vertex of the function g(x) exists (-2, -3).

Now, if (a > 0) then the vertex of the function exists minimum, and if (a < 0) then the vertex of the function exists maximum.

The vertex of the function f(x) exists at a maximum and the vertex of the function g(x) exists at a minimum.

To learn more about the vertex of the function refer to:

brainly.com/question/11325676

#SPJ4

8 0
2 years ago
Can anyone help me on this question?
slavikrds [6]
Cant view the picture
7 0
3 years ago
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