I'm pretty sure its a^2+b^2=C^2
![\sqrt[3]{\dfrac{-27}{125}} = -\sqrt[3]{\left(\dfrac{3}{5}\right)^{3}}=\dfrac{-3}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cdfrac%7B-27%7D%7B125%7D%7D%20%3D%20-%5Csqrt%5B3%5D%7B%5Cleft%28%5Cdfrac%7B3%7D%7B5%7D%5Cright%29%5E%7B3%7D%7D%3D%5Cdfrac%7B-3%7D%7B5%7D)
The appropriate choice appears to be ...
B. -3/5
Answer:
C. 1:27
Step-by-step explanation:
a²/b²=1/9 => a=1 and b=3
a³/b³=1³/3³=1/27
C. 1:27
Answer:
greater than 1
Step-by-step explanation:
its greater because 1.01 is greater than 1
Answer:
2094.4 cm³
Step-by-step explanation:
The volume of a cone =πr²h/3
Where
r = radius = Diameter/2
Diameter = 20cm, radius = 20cm/2 = 10cm
Height = 20cm
Volume of a cone = π × 10² × 20/3
Volume of a cone = 2094.3951 cm³
Approximately to the nearest tenth = 2094.4 cm³
Therefore , the volume of a cone = 2094.4 cm³