the height of a ball thrown directly up with a velocity of 40 feet per second from a initial height of 5 ft is given by the equa tion h(t)=-16t2+40t+5, where t is the time in seconds and h is the balls height, measured in feat. when will the ball hit the ground?
1 answer:
The equation is h=-16t²+40t+5.The ball will hit the ground when h=0. So: 0=-16t²+40t+5 16t²-40t-5=0 Using the quadratic formula, we get a positive value for t of <span>2.61930639376 seconds. ☺☺☺☺ </span>
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