Part A.
Using the Pythagorean theorem,
PR² = PQ² +QR²
PR² = (14 ft)² +(6 ft)² = 196 ft² +36 ft² . . . . substitute the given numbers
PR² = 232 ft² . . . . . . . . . . . . . . . . . . . . . . . .find the sum
PR = √(232 ft²) ≈ 15.23 ft . . . . . . . . . . . . . take the square root
The length of rod PR is 15.23 ft.
Part B.
Using the Pythagorean theorem,
PR² = PQ² +QR²
(16 ft)² = (14 ft)² +QR² . . . . . . . substitute the given numbers
256 ft² -196 ft² = QR² . . . . . .. subtract 14²
60 ft² = QR² . . . . . . . . . . . . . . find the sum
√(60 ft²) = QR ≈ 7.75 ft . . . . . take the square root
The new height QR is about 7.75 ft.
Answer:
7x2 + 3y2 - 4x
Step-by-step explanation:
Answer:
The angle measures of Δ VUW are m∠V = 60°, m∠U = 90°, m∠W = 30° ⇒ last answer
Step-by-step explanation:
In any triangle if the sum of the squares of the shortest two sides is equal to the square of the longest side, then the triangle is a right triangle and the angle opposite to the longest side is the right angle
In Δ VUW
∵ WV = 6 cm
∵ WU = 3
cm
∵ UV = 3 cm
- Use the rule above tho check if it is a right Δ or not
∴ The longest side is WV
∴ The shortest two sides are WU and UV
∵ (WV)² = (6)² = 36
∵ (WU)² + (UV)² = (3
)² + (3)² = 27 + 9 = 36
∴ (WV)² = (WU)² + (UV)²
- That means ∠U which opposite to WV is a right angle
∴ Δ VUW is a right triangle at ∠U
∴ m∠U = 90°
Let us use the trigonometry ratios to find m∠W and m∠V
→ sin Ф =
∵ UV is the opposite side of ∠W
∵ WV is the hypotenuse
∵ sin(∠W) = 
∵ sin(∠W) = 
- Use
to find ∠W
∴ ∠W = 
∴ m∠W = 30°
∵ WU is the opposite side of ∠V
∵ WV is the hypotenuse
∵ sin(∠V) = 
∵ sin(∠V) = 
- Use
to find ∠V
∴ ∠V = 
∴ m∠V = 60°
The angle measures of Δ VUW are m∠V = 60°, m∠U = 90°, m∠W = 30°
Answer:
i think she got 10.07 lbs of pork
Step-by-step explanation: