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3 years ago

Best explained and correct answer gets brainliest!

Mathematics

1 answer:

mezya [45]3 years ago

3 0

The answer is B because C and D are not true. Angle-Angle theorem does not prove congruency. Hypotenuse-Leg does because having a hypotenuse means that the triangle is a right angle triangle, which means that 2 sides and an angle are congruent in the triangles. By Side-Side-Angle Theorem, the triangles are congruent.

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Which answer is the approximate standard deviation of the data set?

Ierofanga [76]

Answer: A. 6.5

Step-by-step explanation:

Here, the given set = { 15, 19 3, 12, 17, 2, 2, 8}

Mean, $\overline{ x} = \frac{15+19+3+12+17+2+2+8}{8} = \frac{78}{8} = 9.75$

Number of elements, n = 8

$\frac{\sum (|x-\overline{x}|)^2}{n}=42.4375$

Thus, the standard deviation, $\sigma =\frac{\sqrt{\sum(|x-\overline{x}|)^2} }{n}=\sqrt{\frac{339.5}{8}}=\sqrt{42.4375} = 6.51440711\approx 6.5$

⇒ Option A is correct.

4 0

3 years ago

Read 2 more answers

you have only nicole's and dimes in your piggy bank. when you ran the coins through a change counter, it indicated you have 595

Kryger [21]

Let's say the amount of nickels you have is hmm "n"

and the amount of dimes you have is "d"

there are 5cents in one nickel, so, if "n" is the total amount of nickels you have, that means 5 * n cents or 5n

there are 10cents in one dime, so, if "d" is the total amount of dimes you have, that means 10*d or 10d

whatever 5n and 10d are, we know that their sum is 595
since the total amount the counter said you have is, only 595 cents

thus 5n + 10d = 595

solve for either, "d" or "n", and graph that

what are three likely combinations? well, just pick three points off that graph

3 0

3 years ago

Help please asap just the answers

Stella [2.4K]

$\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$

$\huge\underline{\sf{\red{Problem:}}}$

7.) Detemine the value of $\sf{ {3a}^{2} -b.}$

$\huge\underline{\sf{\red{Given:}}}$

$\quad\quad\quad\quad\sf{a = 2}$

$\quad\quad\quad\quad\sf{b = - 1}$

$\quad\quad\quad\quad\sf{c = - 3}$

$\huge\underline{\sf{\red{Solution:}}}$

$\quad\quad\quad\quad\sf{⟶{3a}^{2} - b}$

$\quad \quad \quad \quad \sf{⟶{(3)( 2)}^{2} -( - 1)}$

$\quad \quad \quad \quad \sf{⟶3(4)-( - 1)}$

$\quad \quad \quad \quad \sf{⟶12-( - 1)}$

$\quad \quad \quad \quad \sf{⟶12 + 1 }$

$\quad \quad \quad \quad ⟶ \boxed{ \sf{ 13}}$

$\huge\underline{\sf{\red{Answer:}}}$

$\huge\quad \quad \underline{ \boxed{ \sf{ \red{7.)\:13}}}}$

8.) Find the value of $\sf{ {a}^{3} {b}^{3} - abc.}$

$\huge\underline{\sf{\red{Solution:}}}$

$\quad\quad\quad\quad\sf{⟶ {a}^{3} {b}^{3} - abc}$

$\quad\quad\quad\quad\sf{⟶{(2)}^{3} {( - 1)}^{3} - (2)( - 1)( - 3)}$

$\quad\quad\quad\quad\sf{⟶{(8)}{( - 1)} - ( - 2)( - 3)}$

$\quad\quad\quad\quad\sf{⟶{( - 8)} - ( 6)}$

$\quad\quad\quad\quad ⟶\boxed{\sf{ - 14}}$

$\huge\underline{\sf{\red{Answer:}}}$

$\huge\quad \quad \underline{ \boxed{ \sf{ \red{8.)-14}}}}$

#CarryOnLearning

$\sf{\red{✍︎ C.Rose❀}}$

4 0

2 years ago

16/21 × 20/24 × 28/15

Troyanec [42]

Answer:

32/27

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let

sergiy2304 [10]

Answer:

(a) P(X=3) = 0.093

(b) P(X≤3) = 0.966

(c) P(X≥4) = 0.034

(d) P(1≤X≤3) = 0.688

(e) The probability that none of the 25 boards is defective is 0.277.

(f) The expected value and standard deviation of X is 1.25 and 1.089 respectively.

Step-by-step explanation:

We are given that when circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%.

Let X = the number of defective boards in a random sample of size, n = 25

So, X ∼ Bin(25,0.05)

The probability distribution for the binomial distribution is given by;

$P(X=r)= \binom{n}{r} \times p^{r}\times (1-p)^{n-r} ; x = 0,1,2,......$

where, n = number of trials (samples) taken = 25

r = number of success

p = probability of success which in our question is percentage

of defectivs, i.e. 5%

(a) P(X = 3) = $\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $2300 \times 0.05^{3}\times 0.95^{22}$

= 0.093

(b) P(X $\leq$ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

= $\binom{25}{0} \times 0.05^{0}\times (1-0.05)^{25-0}+\binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $1 \times 1 \times 0.95^{25}+25 \times 0.05^{1}\times 0.95^{24}+300 \times 0.05^{2}\times 0.95^{23}+2300 \times 0.05^{3}\times 0.95^{22}$

= 0.966

(c) P(X $\geq$ 4) = 1 - P(X < 4) = 1 - P(X $\leq$ 3)

= 1 - 0.966

= 0.034

(d) P(1 ≤ X ≤ 3) = P(X = 1) + P(X = 2) + P(X = 3)

= $\binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$