<span>If this is an isosceles triangle, then it has two 45 degree angles corresponding to two legs of equal length. Orient the base of this triangle so that it's horizontal, and represent its length by b. Let h represent the height of the triangle. Then the area of this right triangle is 50 square inches = (1/2)(b)(h), or A = (b/2)h = 50 in^2.
Due to the 45 degree angles, the height of this triangle is equal to half the base, or h = b/2. Thus, (b/2)h = 50 becomes (b/2)(b/2) = 50, or b^2=200. Thus, b = 10sqrt(2), and h=(1/2)(10 sqrt(2)), or h = 5sqrt(2).
The length of one of the legs is the sqrt of [5sqrt(2)]^2+[5sqrt(2)]^2, or
sqrt(25(2)+25(2)) = sqrt(100) = 10.
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Answer:
(4 , 3 ) and (-3 , -4)
Step-by-step explanation:
Other two vertices will be in 1st quadrant and 3 rd quadrant
Let <em>x</em> = 8.132132132...
Then 1000<em>x</em> = 8132.132132132...
Subtract <em>x</em> from 1000<em>x</em> to eliminate the fractional part:
1000<em>x</em> - <em>x</em> = 8132.132132132... - 8.132132132...
999<em>x</em> = 8132 - 8 = 8124
<em>x</em> = 8124/999 = 2708/333
25 metres. Because 1/10th of a kilometre is a 100 metres. And four athletes divided by 100 metres is 25 metres.
8 divided by 3 is 2.666 that multiplied by 8 = 21.333
