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3 years ago

If the average of L numbers is m. What is the sum of these numbers?

Mathematics

1 answer:

Mamont248 [21]3 years ago

7 0

Answer:

Step-by-step explanation:

average = (sum of numbers)/(number of numbers)

Solve the equation for "sum of numbers":

sum of numbers = average * number of numbers

sum of numbers = m * L

sum of numbers = Lm

Answer: B) Lm

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In bowling, you get a spare when you knock down the ten pins in two throws. How many possible ways are there to get a spare?

balu736 [363]

There are 9 ways to get a spare
1 and 9
2 and 8
3 and 7
4 and 6
5 and 5
6 and 4
7 and 3
8 and 2
9 and 1

4 0

3 years ago

Read 2 more answers

To compute the area of a rectangle, you need to use the formula A=l.w if the length is 2 3/4 inches and the width is 4 1/2 inche

blagie [28]

Answer:

12 3/8

Step-by-step explanation:

A = 2 3/4 x 4 1/2

best way is to change mixed numbers to fractions and multiply and then go back to a mixed number.

11/4 x 9/2 = 99/8 = 12 3/8

8 0

3 years ago

A line’s equation is given in point-slope form:

navik [9.2K]

we conclude that the point on this line that is apparent from the given equation is (-6, 6)

<h3>Which point is on the line, only by looking at the equation?</h3>

Remember that a general linear equation in slope-intercept form is:

y = a*x + b

Where a is the slope.

Here we have the linear equation:

y - 6= (-23)*(x + 6)

Now, for a linear equation with a slope a and a point (h, k), the point slope form of the linear equation is:

(y - k) = a*(x - h)

Now we can compare that general form with our equation, we will get:

(y - k) = a*(x - h)

(y - 6) = (-23)*(x + 6)

Then we have: k = 6 and h = -6.

Thus, we conclude that the point on this line that is apparent from the given equation is (-6, 6).

If you want to learn more about linear equations:

brainly.com/question/1884491

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4 0

1 year ago

Media experts claim that daily print newspapers are declining because of Internet access. Listed below, from left to right and

yKpoI14uk [10]

Answer:

(a) The median is 1478

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

(d) The p value is 1.2×10⁻¹¹

(e) We reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high

Step-by-step explanation:

(a) Here we have the data as follows;

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484 1478 1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The median is = 1478

Therefore we have above the median

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484

The mean, $\bar{x}_{1}$ = 1541.9

Standard deviation, σ₁ = 41.38224257

n₁ = 10

Below the median

1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The mean, $\bar{x}_{2}}$ = 1433.9

Standard deviation, σ₂ = 30.04812806

n₂ = 10

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

$t_{\alpha/2} =\frac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}$

df = 10 - 1 = 9, α = 0.05

Therefore, the test statistic $t_{\alpha/2}$ = 6.678155

(d) The p value from statistical relations is Probability p = 1.2×10⁻¹¹

Critical z at 5% confidence level = 1.645

Since P << 0.05, e reject the

(e) Therefore, we reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high.

5 0

3 years ago

shopkeeper purchased a bicycle for rupees 5000 and marked its price a certain percent above the cost price then he sold it at 10

Gennadij [26K]

Lets say the final price of the bike is SP plus 13% VAT. So:

1.13 * SP = 6356.25

SP = 5625

Now SP was after 10% discount on Original Price, say MP. So:

0.9 * MP = 5625

MP = 6250

Therefore, the percent of Marked Price above Cost Price is:

(6250 - 5000) * 100/5000 = 25%

8 0

3 years ago