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marysya [2.9K]
4 years ago
7

For each pair of numbers, tell: By what percent of the first number is the second number larger? By what percent of the second n

umber is the first number smaller? 100 and 110
Mathematics
1 answer:
marishachu [46]4 years ago
3 0
The answer for the first question is 10%.
Reason: The second number (110) is larger than the first number (100) by 10 it is 10% the first number.
.
The answer for the second question is 25%, also.
Reason: The first number (100) is smaller than the second number (110) by 10 and it is 9.1% of the second number.
:)
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erastovalidia [21]

Answer:

x = 25

Step-by-step explanation:

Given:

  • ∠A = ∠B    (Vertically opposite angles)
  • ∠A = (7x - 8)°
  • ∠B = (6x + 17)°

Since ∠A is equivalent to ∠B...

\implies (7x - 8)= (6x + 17)

Open the parenthesis:

\implies 7x - 8= 6x + 17

Add 8 both sides:

\implies 7x - 8 + 8= 6x + 17 + 8

Simplify both sides:

\implies 7x = 6x + 25

Subtract 6x both sides:

\implies 7x - 6x = 6x - 6x + 25

Simplify both sides:

\implies x = 25

7 0
2 years ago
Read 2 more answers
7,300 deposit earning 3.3% compounded monthly after 1 year. What will the balance after 1 year will be?
inna [77]

Answer:

$7,544.58

Step-by-step explanation:

We will use the compound interest formula provided to solve this:

A=P(1+\frac{r}{n} )^{nt}

<em>P = initial balance</em>

<em>r = interest rate (decimal)</em>

<em>n = number of times compounded annually</em>

<em>t = time</em>

<em />

First, change 3.3% into its decimal form:

3.3% -> \frac{3.3}{100} -> 0.033

Since the interest is compounded monthly, we will use 12 for n. Lets plug in the values now:

A=7,300(1+\frac{0.033}{12})^{12(1)}

A=7,544.58

The balance after 1 year will be $7,544.58

7 0
4 years ago
Evaluate the expression, when x = 3.2x + 4(x - 2)a910ObocOd118
love history [14]

The initial expression is:

2x + 4(x - 2)

Replacing x by 3, we get:

2(3) + 4(3 - 2)

6 + 4(1)

6 + 4

10

The value of the expression is 10

4 0
1 year ago
Chantel starts a savings account with $37. Each month she deposits $15 more into her account. Chantel now has saved $97. Which e
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5 0
3 years ago
how many gallons of a 50 antifreeze solution must be mixed with 90 gallons of 20% antifreeze to get a mixture that is 40% antifr
Tamiku [17]
Try this:
1) note that weight of pure antifreeze before mixing and after mixing is the same. So, if 'x' is weight of pure antifreeze in 50% solution, it is possible to make up equation before mixing: 0.5x+0.2*90.
2) there are 0.2*90=18 gal. of pure antifreeze in the 20% solution. If 'x' gal. is the weight of pure antifreeze in 50% sol. and 18 gal. is the weight of pure antifreeze in 20% sol., it is possible to make up an equation after mixing: 0.4(x+18).
3) using the both parts: 0.5x+0.2*90=0.4(x+18) ⇒ x=54 gal. of <u>pure</u> weight.
4) to find 50% solution of 54 gal. pure weight just 54:0.5=108 gal.
Answer: 108 gal.
3 0
3 years ago
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