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alexandr1967 [171]
3 years ago
5

What is 7 to the 4 world power in expanded form?

Mathematics
1 answer:
Murrr4er [49]3 years ago
8 0
"world" power ???

Don't you mean "what is 7 to the 4th power?"

It's (7)(7)(7)(7) = (49)(49), or approx. 2,500.  Multiply out 49(49) for the exact answer.

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22.4

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Which function has the greatest starting value?. . A.. xy. 1−3. 2−8. 3−13. . . B.. y = 3x – 8. . C.. 8x + 4y = 16. . D.. A linea
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4 years ago
a father was four times older than his son. ten years ago,if their present age is 423 find the age of father and son?​
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7 0
3 years ago
Use linear regression to find the equation for the linear function that best fits this data. Round both numbers to two decimal p
natta225 [31]

Answer:

The equation of the linear function that best fits the data is,

<em>y</em> = 18.66<em>x</em> + 66.87.

Step-by-step explanation:

The line of best is of the form: <em>y</em> = <em>mx</em> + <em>b</em>.

Here, <em>m</em> = slope of the line and <em>b</em> = intercept.

The formula to compute the intercept and slope are:

b=\frac{\sum Y.\sum X^{2}-\sum X.\sum XY}{n.\sum X^{2}-(\sum X)^{2}}

m=\frac{n.\sum XY-\sum X.\sum Y}{n.\sum X^{2}-(\sum X)^{2}}

Consider the table below for the values of <em>∑ X, ∑ Y, ∑ X² </em>and <em>∑ XY</em>.

Compute the value of  intercept and slope as follows:

b=\frac{\sum Y.\sum X^{2}-\sum X.\sum XY}{n.\sum X^{2}-(\sum X)^{2}}=\frac{(793\times91)-(21\times3102)}{(6\times91)-(21)^{2}} =66.867

m=\frac{n.\sum XY-\sum X.\sum Y}{n.\sum X^{2}-(\sum X)^{2}}=\frac{(6\times3102)-(21\times793)}{(6\times91)- (21)^{2}} =18.657

The line of best fit is:

y=mx+b\\y=18.657x+66.867\\y=18.66x+66.87

Thus, the equation of the linear function that best fits the data is <em>y</em> = 18.66<em>x</em> + 66.87.

3 0
3 years ago
Marcellus has a pitcher that contained 5/8 gallon limeade. Marcellus drank 1/4 gallon of the limeade, and Marcy drank 1/8 gallon
mash [69]

Answer:

2/5

Step-by-step explanation:

Given Marcellus drank 1/4 gallon of the limeade and Marcy drank 1/8 gallon of the limeade

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Total amount drunk = amount drunk by Marcellus + amount drunk by Marcy

Total amount drunk = \frac{1}{4} +\frac{1}{8} = \frac{3}{8}

The amount of Limeade remained = The amount initially - the amount drunk

The amount remained =  \frac{5}{8} -\frac{3}{8} = \frac{1}{4}

Fractional part = amount remained / amount initially = \frac{\frac{1}{4} }{\frac{5}{8} } = \frac{2}{5}

8 0
3 years ago
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