The question is incorrect so the answer consists of the genetic context of meiosis.
Answer:
Two main types of cell division are mitosis and meiosis. Meiosis is the process of cell cycle division in which the parents cell divides into the four daughter cells. This division is also known as reductional division.
In meiosis, the gametes are haploid where as the parent cell is diploid in nature. The cell undergoes the two meiosis division, the first division is reductional in nature whereas the second meiosis division is same as the mitotic division. This division occurs in the sex cells and results in the formation of haploid gamete hat restores deiploidy during fertilization process. Crossing over during meiosis bring variation in the cells.
It’s natural LOL , it can’t be man - made . It depends where you live it though .
The restriction endonuclease EcoRI cleaves the DNA sequence 5'-GAATTC-3' in such a way as to leave a 5' overhang, which is often referred to as a "sticky end". To 5' overhang with the complementary sequence this sticky end adhere.
- The palindrome EcoRI restriction site breaks DNA after G and creates sticky ends with AATT. G/corresponding AATTC's DNA sequence is CTTAA/G, where "/" designates the location of the peptide bond break.
- When the ssDNA sequence 5'-GAATTC'-3 is recognised by the restriction endonuclease EcoRI, a single-strand cut is made between the G and A nucleotides.
- At the ultimate end of double-stranded DNA, an overhang is single-stranded DNA. This can occur on either strand, and if it does, there will either be a 5' overhang on the 5' end of the strand or a 3' overhang on the 3' end of the strand.
To learn more about DNA.
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<span>The answer is the option a. Filter feeders - strain food from water. You can realize the the option b is no rirght because carnivores eat meat (other aninals), c is not rigth because paraistes do not help other animals but they harm other animals, and d. is not right because herbivores eat plants and not bits of decaying matter. So you can eliminate b, c, and d. While a. reflects exactly what filter feeders eat.</span>
Answer:
Genotypic ratio of offsprings will be: 1 (Hh) : 1 (hh)
Explanation:
This question involves a single gene coding for the possession or not of Hitchhiker's thumb in humans. The allele that codes for Hitchhiker's thumb (H) is dominant over the allele for no hitchhiker's thumb (h).
Based on this question, if woman who does not have hitchhiker's thumb (hh) marries a man who is heterozygous for hitchhiker's thumb (Hh) i.e. hh × Hh, the following gametes will be produced by each parent:
hh - h and h
Hh - H and h
Using these gametes in a punnet square (see attached image), the offsprings with the following genotypic ratio will be likely produced:
1 (Hh) : 1 (hh)
N.B:
- Two (2) of them were Hh i.e. with Hitchhiker's thumb
- The other two were hh i.e. no hitchhiker's thumb.
