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ch4aika [34]
3 years ago
12

If a coach costs £220 to hire, what will the cost be if the coach company raise their price by 12%?​

Mathematics
1 answer:
Levart [38]3 years ago
6 0

Answer:

£246.40

Step-by-step explanation:

if 12 percent of £220 is 26.40, you'll add them together. That gives you £246.40.

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What is the constant of proportionality in y=5x
-BARSIC- [3]

Answer:

<em>5</em>

Step-by-step explanation:

General equation of direct variation:

y = kx,

where k is the constant of proportionality.

In your case, you have

y = 5x, so 5 is the constant of proportionality.

8 0
3 years ago
Sahana sells two products for ₹. 8000 each gaining 8% on one and losing 6% on the other. Find her gain or loss percent in the wh
Margaret [11]

Based on the information given the gain or loss percent on the whole transaction​ is 1%.

<h3>Gain or loss percent: </h3>

First step is to calculate the profit on the whole transaction

Profit=(8%×8,000)-(6%×8,000)

Profit=$640-$480

Profit=$160

Now let calculate the gain or loss percentage on the whole transaction

Gain or loss percentage=160/(8000+8000)×100

Gain or loss percentage=160/16000×100

Gain or loss percentage=1%

Inconclusion the gain or loss percent on the whole transaction​ is 1%.

Learn more about gain or loss here:brainly.com/question/25278228

5 0
2 years ago
Use the distributive property to fill in the blanks below.
elena-14-01-66 [18.8K]

Answer:

(5×7)-(5×6) = 5×(7-6)

5 0
3 years ago
Events A and B have probabilities such that P(A) = 0.3, P(B) = 0.25, P(M ∪ N) = 0.425, and P(M ∩ N) = 0.075. Are events A and ev
nekit [7.7K]

Answer:

(C)Yes, because P(M) ∙ P(N) = P(M ∩ N)

Step-by-step explanation:

Two events A and B are independent if P(A)P(B)=P(A ∩ B)

Given events A and B such that:

P(A) = 0.3, P(B) = 0.25, P(A ∪ B) = 0.425, and P(A ∩ B) = 0.075

  • P(A)P(B)=0.3 X 0.25 =0.075
  • P(A ∩ B) = 0.075

Since the two expression above gives the same answer, they are independent.

<u>The correct option is C.</u>

7 0
3 years ago
The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar
Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

\bar x represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

\chi^2_{\alpha/2}=19.022

\chi^2_{1- \alpha/2}=2.700

And replacing into the formula for the interval we got:

\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}

10.892 \leq \sigma^2 \leq 76.736

Now we just take square root on both sides of the interval and we got:

3.30 \leq \sigma \leq 8.76

So the best option would be:

3.30<σ<8.76

7 0
3 years ago
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