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Gnesinka [82]
3 years ago
11

#38: The integers below represent the monthly gains and losses in the value of an investment over one year. Find the mean of the

integers: -$190, $75, -$65, $100, $72, -$54, -$62, -$87, $92, $81, -$73, $63

Mathematics
1 answer:
jek_recluse [69]3 years ago
8 0
It should be $84.50 because you have to add all the numbers up and divide it by how many numbers there are
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The rule Rx-axis o is applied to the point (-3,-2). Where is the image in the coordinate
Nastasia [14]

Answer:

Image = (-3,2)

Step-by-step explanation:

Given

Point = (-3,-2)

Transformation = Rx-axis

Required

Determine the image

When rule Rx-axis is applied to a point (x,y),

The new coordinate point is (x,-y)

<em>In other words, the y coordinate is negated</em>

So, when rule Rx-axis is applied to

Point = (-3,-2)

The image of the point is

Image = (-3,-(-2))

Image = (-3,2)

4 0
3 years ago
What is the value of x if y = 4
enyata [817]

Answer:

x is infinite

Step-by-step explanation:

x is a function so

if y=f:x

therefore

0 < x <  \infty

5 0
3 years ago
I have more question then this
gregori [183]

Answer:

A. A reflection over the x-axis

8 0
3 years ago
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Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = ln x, [1,7] choose one letter t
inn [45]
ANSWER

B.Yes, f is continuous on [1, 7] and differentiable on (1, 7).

c\approx 3.08

EXPLANATION

The given

f(x) = ln(x)

The hypotheses are

1. The function is continuous on [1, 7].

2. The function is differentiable on (1, 7).

3. There is a c, such that:

f'(c) = \frac{f(7) - f(1)}{7 - 1}

f'(x) = \frac{1}{x}

This implies that;

\frac{1}{c} = \frac{ ln(7) - 0}{6}

\frac{1}{c} = \frac{ ln(7)}{6}

c = \frac{6}{ ln(7) }

c\approx 3.08

Since the function is continuous on [1, 7] and differentiable on (1, 7) it satisfies the mean value theorem.
7 0
3 years ago
HELP RIGHT NOW AND ILL GIVE BRAINLY IF CORRECT
Stella [2.4K]

Answer:

-9

Step-by-step explanation:

3^{-36}= 27^{-12}

7 0
3 years ago
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