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3 years ago

Solve for all valúes of x

Mathematics

1 answer:

malfutka [58]3 years ago

7 0

Answer:

2x/(x+3) +3/(x-3) = 8/(x^2

[2x(x-3) +3(x+3)]\( x^2 - 9) =8/(x^2 -9)

2x^2 -6x +3x +9=8 (x^2 -9) /(x^2 -9)

2 x^2 -3x +9 -8=0

2 x^2 -3x +1 =0

2x^2 -2x -1x +1 =0

2x(x-1) -1(x-1)=0

(x-1)(2x-1)=0

either, or, 2x-1=0

x-1 =0 2x =1

x =1 x= 1/2

hence, x= 1, 1/2

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